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这是文件选择器的代码，
我需要将用户打开的图像复制到应用文件夹。任何人都可以帮助我

private async void Button_Click(object sender, RoutedEventArgs e)
    {

        if (Windows.UI.ViewManagement.ApplicationView.Value != Windows.UI.ViewManagement.ApplicationViewState.Snapped ||
             Windows.UI.ViewManagement.ApplicationView.TryUnsnap() == true)
        {
            Windows.Storage.Pickers.FileOpenPicker openPicker = new Windows.Storage.Pickers.FileOpenPicker();
            openPicker.SuggestedStartLocation = Windows.Storage.Pickers.PickerLocationId.PicturesLibrary;
            openPicker.ViewMode = Windows.Storage.Pickers.PickerViewMode.Thumbnail;

            // Filter to include a sample subset of file types.
            openPicker.FileTypeFilter.Clear();
            openPicker.FileTypeFilter.Add(".bmp");
            openPicker.FileTypeFilter.Add(".png");
            openPicker.FileTypeFilter.Add(".jpeg");
            openPicker.FileTypeFilter.Add(".jpg");

// 打开文件选择器。

        Windows.Storage.StorageFile file = await openPicker.PickSingleFileAsync();

            // file is null if user cancels the file picker.
            if (file != null)
            {
                // Open a stream for the selected file.
                Windows.Storage.Streams.IRandomAccessStream fileStream =
                    await file.OpenAsync(Windows.Storage.FileAccessMode.Read);

// 将图像源设置为选定的位图。`

                Windows.UI.Xaml.Media.Imaging.BitmapImage bitmapImage =
                    new Windows.UI.Xaml.Media.Imaging.BitmapImage();

                bitmapImage.SetSource(fileStream);
                img.Source = bitmapImage;
                this.DataContext = file;


            }
        }

    }

谢谢

4

1 回答 1

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使用StorageFile.CopyAsync，即 file.CopyAsync。第一个参数是目标 StorageFolder，例如 Windows.Storage.ApplicationData.Current.LocalFolder，如果你想复制到 appdata；否则您需要创建一个文件夹或单独从选择器中获取一个。

例如，您可以让用户使用文件选择器（为文件夹配置）选择一个默认文件夹。请务必将该 StorageFolder 保存在 中，[Windows.Storage.AccessCache][2]以保留编程访问以供将来使用。

于 2013-04-25T19:31:56.057 回答