我需要创建三个动态下拉列表，第二个基于第一个的选择，第三个基于第二个的选择，但我遇到一个问题，即第二个和第三个显示默认值而没有任何选项可供选择另一个价值观
谁能帮我？？？
数据库配置文件
<?php
$host = "localhost";
$user = "****";
$password = "****";
$db = "lam_el_chamel_db";
?>
选择.php
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("select#district").attr("disabled","disabled");
$("select#village").attr("disabled","disabled");
$("select#governorate").change(function(){
$("select#district").attr("disabled","disabled");
$("select#district").html("<option>wait...</option>");
var id = $("select#governorate option:selected").attr('value');
$.post("select_district.php", {id:id}, function(data){
$("select#district").removeAttr("disabled");
$("select#district").html(data);
});
});
$("select#district option:selected").change(function(){
id = $(this).val();
$.post("select_village.php", {id:id}, function(data){
$("select#village").attr("disabled","disabled");
$("select#village").html("<option>wait...</option>");
$("select#village").removeAttr("disabled");
$("select#village").html(data);
});
$("form#select_form").submit(function(){
var cat = $("select#governorate option:selected").attr('value');
var type = $("select#district option:selected").attr('value');
var vil = $("select#village option:selected").attr('value');
if(cat>0 && type>0 && vil>0)
{
var result = $("select#district option:selected").html();
$("#result").html('your choice: '+result);
}
else
{
$("#result").html("you must choose two options!");
}
return false;
});
});
</script>
</head>
<body>
<?php include "select.class.php"; ?>
<form id="select_form">
Choose a governorate:<br />
<select id="governorate" name = 'governorate'>
<?php echo $opt->ShowGovernorate(); ?>
</select>
<br /><br />
choose a district:<br />
<select id="district">
<option value="0">choose...</option>
</select>
<br /><br />
choose a village:<br />
<select id="village">
<option value="0">choose...</option>
</select>
<br /><br />
<input type="submit" value="confirm" />
</form>
<div id="result"></div>
</body>
</html>
选择类.php
<?php
class SelectList
{
protected $conn;
public function __construct()
{
$this->DbConnect();
}
protected function DbConnect()
{
include "dbconfig.php";
$this->conn = mysql_connect($host,$user,$password) OR die("Unable to connect to the database");
mysql_select_db($db,$this->conn) OR die("can not select the database $db");
return TRUE;
}
public function ShowGovernorate()
{
$sql = "SELECT * FROM governorate";
$res = mysql_query($sql,$this->conn);
$governorate = '<option value="0">choose...</option>';
while($row = mysql_fetch_array($res))
{
$governorate .= '<option value="' . $row['governorate_id'] . '">' . $row['governorate_name'] . '</option>';
}
return $governorate;
}
public function ShowDistrict()
{
$sql = "SELECT * FROM districts WHERE governorate_id=$_POST[id]";
$res = mysql_query($sql,$this->conn);
var_dump($res);
$district = '<option value="0">choose...</option>';
while($row = mysql_fetch_array($res))
{
$district .= '<option value="' . $row['district_id'] . '">' . $row['district_name'] . '</option>';
}
return $district;
}
public function ShowVillage()
{
$sql = "SELECT village_id, village_name FROM village WHERE district_id=$_POST[id]";
$res = mysql_query($sql,$this->conn);
$village = '<option value="0">choose...</option>';
while($row = mysql_fetch_array($res))
{
$village .='<option value="' .$row['village_id'] . '">' . $row['village_name'] . '</option>';
}
return $village;
}
}
$opt = new SelectList();
?>
选择区.php
<?php
include "select.class.php";
echo $opt->ShowDistrict();
?>
select_village.php
<?php
include "select.class.php";
echo $opt->ShowVillage();
?>