0

所以我需要将这条语句输出的所有行插入到单独的表中：

    SELECT * FROM children WHERE quoteid = '$quoteid'

这仅插入其中一行：

    INSERT INTO beneficiaries (quoteid, uid, name, percent) VALUES('$quoteid', '$uid', '$nm', '10')

任何人都知道移动多行的方法还是我必须单独发送它们？

更新：

之前应该提到过这一点，但不，'children' 没有相同的列名，更改它们不是一种选择。对不起！

$query = mysql_query("SELECT * FROM beneficiaries WHERE quoteid = '$quoteid'");
$getchildrenrid2 = mysql_fetch_assoc($query);

if(mysql_num_rows($query) == 0)
{
    $getchildren = mysql_query("SELECT * FROM children WHERE quoteid = '$quoteid'");
    $getchildrenrid = mysql_fetch_assoc($getchildren);

        $nm = $getchildrenrid['first_name'] . " " . $getchildrenrid['surname'];
        $query = mysql_query("INSERT INTO beneficiaries (quoteid, uid, name, percent) VALUES('$quoteid', '$uid', '$nm', '10')");

    $query = mysql_query("SELECT * FROM beneficiaries WHERE quoteid = '$quoteid'");
        $getlastchild = mysql_fetch_assoc($query);

            header("Location: ".$conf['location']."/distribution.php?edit=".$getlastchild['id']);
}

“儿童”列：

- id
- **quoteid**
- **uid**
- *first_name*
- middle_names
- *surname*
- dob
- guardian_first_name
- guardian_middlenames
- guardian_nickname
- guardian_surname
- guardian_housenum
- guardian_city
- guardian_street
- guardian_postcode

“受益人”列

- id
- **quoteid**
- **uid**
- *name*
- **percent**

需要复制的内容：

  • 报价单 INTO报价单
  • uid 进入 uid
  • 名字 + 姓氏 INTO 名字
  • 并将百分比设置为“10”

此外，这应该只在此之后完成： SELECT * FROM children WHERE quoteid = '$quoteid' 完成。

$quoteid 返回当前报价的唯一quoteid。

4

4 回答 4

1

假设children具有相同的列名...

INSERT INTO beneficiaries (quoteid, uid, name, percent)
SELECT quoteid, uid, name, percent FROM children WHERE quoteid = '$quoteid'
于 2013-04-24T14:14:01.970 回答
1

尝试这个：

INSERT INTO beneficiaries (quoteid, uid, name, percent) select
quoteid, uid, name, percent from children WHERE quoteid = '$quoteid';
于 2013-04-24T14:15:00.160 回答
0

INSERT INTO beneficiaries (quoteid, uid, name, percent) SELECT quoteid, uid, name, percent FROM children WHERE quoteid = '$quoteid';

根据需要调整列名。

于 2013-04-24T14:14:09.733 回答
0

INSERT INTO beneficiaries (quoteid, uid, name, percent) SELECT (quoteid, uid, name, percent) FROM children WHERE quoteid = '$quoteid'

当然，假设列是兼容的，该查询将按照您的要求进行。

来源：MySQL 文档：INSERT ... SELECT

于 2013-04-24T14:14:22.913 回答