我有一个不同尺寸的图片库。ImageView
每个图像都按顺序(通过)显示在内部OnTouchListener
。我需要知道我展示亲戚的图片框架的位置,ImageView
但是通过我所做的测试,我只得到了ImageView
. 任何想法?
我需要 (x1, y1) 和 (x2, y2) 的值。
提前致谢。
这是我的课:
public class PuzzleView extends ImageView {
protected Paint currentPaint;
protected boolean drawRect = false;
protected float left;
protected float top;
protected float right;
protected float bottom;
protected float pixelX;
protected float pixelY;
protected int nChunksX = 5;
protected int nChunksY = 5;
protected int currentWidth = 0;
protected int currentHeight = 0;
public PuzzleView(Context context, AttributeSet attrs) {
super(context, attrs);
currentPaint = new Paint();
currentPaint.setDither(true);
currentPaint.setColor(0xFF00CC00);
currentPaint.setStyle(Paint.Style.STROKE);
currentPaint.setStrokeJoin(Paint.Join.ROUND);
currentPaint.setStrokeCap(Paint.Cap.ROUND);
currentPaint.setStrokeWidth(2);
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
float chunkWidth = currentWidth / nChunksX;
float chunkHeight = currentHeight / nChunksY;
float posX = ((int)(pixelX / chunkWidth)) * chunkWidth;
float posY = ((int)(pixelY / chunkHeight)) * chunkHeight;
canvas.drawRect(posX, posY, posX + chunkWidth, posY + chunkHeight, currentPaint);
Rect rect = this.getDrawable().getBounds();
canvas.drawRect(rect, currentPaint);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
super.onMeasure(widthMeasureSpec, heightMeasureSpec);
// Get image matrix values and place them in an array
float[] f = new float[9];
getImageMatrix().getValues(f);
// Extract the scale values using the constants (if aspect ratio maintained, scaleX == scaleY)
final float scaleX = f[Matrix.MSCALE_X];
final float scaleY = f[Matrix.MSCALE_Y];
// Get the drawable (could also get the bitmap behind the drawable and getWidth/getHeight)
final Drawable d = getDrawable();
final int origW = d.getIntrinsicWidth();
final int origH = d.getIntrinsicHeight();
// Calculate the actual dimensions
final int actW = Math.round(origW * scaleX);
final int actH = Math.round(origH * scaleY);
currentWidth = actW;
currentHeight = actH;
}
public boolean isDrawRect() {
return drawRect;
}
public void setDrawRect(boolean drawRect) {
this.drawRect = drawRect;
}
public float getLeftRect() {
return left;
}
public void setLeftRect(float left) {
this.left = left;
}
public float getTopRect() {
return top;
}
public void setTopRect(float top) {
this.top = top;
}
public float getRightRect() {
return right;
}
public void setRightRect(float right) {
this.right = right;
}
public float getBottomRect() {
return bottom;
}
public void setBottomRect(float bottom) {
this.bottom = bottom;
}
public float getPixelX() {
return pixelX;
}
public void setPixelX(float pixelX) {
this.pixelX = pixelX;
}
public float getPixelY() {
return pixelY;
}
public void setPixelY(float pixelY) {
this.pixelY = pixelY;
}
public int getChunksX() {
return nChunksX;
}
public void setChunksX(int nChunksX) {
this.nChunksX = nChunksX;
}
public int getChunksY() {
return nChunksY;
}
public void setChunksY(int nChunksY) {
this.nChunksY = nChunksY;
}
}
目前,源图像在 XML 文件中定义:
<com.jocajica.shakepic.PuzzleView
android:id="@+id/imageViewSelected"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:contentDescription="@string/image_selected"
android:src="@android:drawable/progress_indeterminate_horizontal" />
我需要在图像上绘制一个网格。