php - 从 Facebook RSS 提要中提取外部图像 url

Question

我有一个看起来像这样的 Facebook 页面 Feed，

http://external.ak.fbcdn.net/safe_image.php?d=AQA-U_vFlmf0YW5c&w=130&h=130&url=http%3A%2F%2Fi1.ytimg.com%2Fvi%2FX9Hx6nUTSwE%2Fmaxresdefault.jpg%3Ffeature%3Dog

如何提取 &url.........featuredog (Extracting only image url) 之间的内容？欣赏任何代码示例。

Answer 1

我的正则表达式很丑，但可以解决问题：

<?php
$str = 'http://external.ak.fbcdn.net/safe_image.php?d=AQA-U_vFlmf0YW5c&w=130&h=130&url=http%3A%2F%2Fi1.ytimg.com%2Fvi%2FX9Hx6nUTSwE%2Fmaxresdefault.jpg%3Ffeature%3Dog';

$str = urldecode($str);
preg_match_all('~&url=(.*?)[\?\!]?feature~i', $str, $matches, PREG_PATTERN_ORDER);

echo $matches[1][0];
?>

Answer 2

$parts = parse_url('http://external.ak.fbcdn.net/safe_image.php?d=AQA-U_vFlmf0YW5c&w=130&h=130&url=http%3A%2F%2Fi1.ytimg.com%2Fvi%2FX9Hx6nUTSwE%2Fmaxresdefault.jpg%3Ffeature%3Dog');
parse_str($parts['query'], $params);
var_dump($params['url']);