我有一张表,用于存储有关用户的信息。该表具有以下结构:
CREATE TABLE PERSONS
(
ID NUMBER(20, 0) NOT NULL,
FIRSTNAME VARCHAR2(40),
LASTNAME VARCHAR2(40),
BIRTHDAY DATE,
CONSTRAINT PERSONEN_PK PRIMARY KEY
(ID)
ENABLE
);
插入一些测试数据后:
SET DEFINE OFF;
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('1','Max','Mustermann',to_date('31.10.89','DD.MM.RR'));
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('2','Max','Mustermann',to_date('31.10.89','DD.MM.RR'));
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('3','Carl','Carlchen',to_date('01.01.12','DD.MM.RR'));
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('4','Max','Mustermann',to_date('31.10.89','DD.MM.RR'));
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('5','Max','Mustermann',to_date('31.10.89','DD.MM.RR'));
Insert into PERSONS (ID,FIRSTNAME,LASTNAME,BIRTHDAY) values ('6','Carl','Carlchen',to_date('01.01.12','DD.MM.RR'));
我想选择给定用户的所有重复项。让我们以“Max Mustermann”为例:
SELECT p.id,p.firstname,p.lastname,p.birthday
FROM persons p
WHERE p.firstname = 'Max'
AND p.lastname = 'Mustermann'
AND p.birthday = to_date('31.10.1989','dd.mm.yyyy')
ORDER BY p.firstname,p.lastname;
这给了我这样的结果:
id first last birthday
=================================
1 Max Mustermann 31.10.89
2 Max Mustermann 31.10.89
4 Max Mustermann 31.10.89
5 Max Mustermann 31.10.89
我想做一个不区分大小写的比较,所以我使用较低(和修剪)更改查询,如下所示:
SELECT p.id,p.firstname,p.lastname,p.birthday
FROM persons p
WHERE lower(trim(p.firstname)) = lower(trim('mAx '))
AND lower(trim(p.lastname)) = lower(trim(' musteRmann '))
AND p.birthday = to_date('31.10.1989','dd.mm.yyyy')
ORDER BY p.lastname,p.firstname;
现在惊喜的顺序已经改变了!
id first last birthday
=================================
1 Max Mustermann 31.10.89
5 Max Mustermann 31.10.89
4 Max Mustermann 31.10.89
2 Max Mustermann 31.10.89
为什么顺序会改变,只需使用 lower()(不使用 trim() 时结果相同)!?我可以通过将 id 列添加到 ORDER BY 来获得稳定的排序。但是 lower() 不应该对排序没有影响吗?
解决方法也为 ORDER BY 使用 id 列:
SELECT p.id,p.firstname,p.lastname,p.birthday
FROM persons p
WHERE p.firstname = 'Max'
AND p.lastname = 'Mustermann'
AND p.birthday = to_date('31.10.1989','dd.mm.yyyy')
ORDER BY p.firstname,p.lastname,p.id;
SELECT p.id,p.firstname,p.lastname,p.birthday
FROM persons p
WHERE lower(trim(p.firstname)) = lower(trim('mAx '))
AND lower(trim(p.lastname)) = lower(trim(' musteRmann '))
AND p.birthday = to_date('31.10.1989','dd.mm.yyyy')
ORDER BY p.lastname,p.firstname,p.id;