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我正在尝试为/s/<4-6 character string here>将 4-6 个字符串捕获为 $1 的路径设置一个正则表达式。

我尝试使用以下两个条目,但都失败了

location ~ ^/s/([0-9a-zA-Z]){4,6}+$ { ...

location ~ ^/s/([0-9a-zA-Z]{4,6})+$ { ...

第一个出现“未知指令”,第二个出现“pcre_compile()失败:缺少)”

编辑

此位置将提供以下路线:

/s/1234 (and I would capture '1234' in $1)
/s/12345 (and I would capture '12345' in $1)
/s/123456 (and I would capture '123456' in $1)
/s/abcd (and I would capture 'abcd' in $1)
/s/abcde (and I would capture 'abcde' in $1)
/s/abcdef (and I would capture 'abcdef' in $1)
/s/a1b2c (and I would capture 'a1b2c' in $1)

此位置不提供以下路线:

/s/1
/s/12
/s/123
/s/a
/s/ab
/s/abc
/s/abc1234
/s/12345678

ETC...

4

1 回答 1

36

如果要捕获 4 到 6 个字符,为什么不将量词放在捕获括号内?

可能是这样的:

location ~ "^/s/([0-9a-zA-Z]{4,6})$" {...

花括号用于正则表达式和块控制,您必须用引号(单引号或双引号)将您的正则表达式括起来(<--wiki nginx)

于 2013-04-23T18:10:17.410 回答