1

所以我是 C 新手，正在自学字符串处理。据我所知，我的问题是我标记 sp 的函数？输入的数字字符串不仅在空格上分裂。例如：如果我输入一个像 45 这样的数字，我的数组中的结果字符串将同时显示 45 和 5，因此无论出于何种原因，它都会在两位数中拆分数字。我已经搜索了很长时间，但没有任何运气。

希望这不是我忽略的明显错误。但是我已经到了无法继续学习的地步，因此不胜感激！

示例输出：

please enter your string: 1 45 30 82
converting strings to ints
Printing the string
 1, 0, 45, 5, 0, 30, 0, 0, 82, 2,
Press any key to continue . . .

我的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <assert.h>

#define STRING_LENGTH 81
#define MAX_TOKENS 40

int StrInput( char dataStr[]);
void atoiWorker( char dataStr[], char results[], int idx);
void printer ( char dataStr[], int idx);
void tokenize ( char dataStr[], char results[]);

int main()
{
    int idx;
    char dataStr[STRING_LENGTH];
    char results[STRING_LENGTH];
    idx = StrInput(dataStr);
    tokenize(dataStr, results);
    atoiWorker(dataStr, results, idx);
    printer(results, idx);
}

int StrInput(char dataStr[])
{
    int idx = 0;
    printf( "please enter your string: " );
    while (idx < (STRING_LENGTH) && ((dataStr[idx] = getchar()) != '\n'))
        idx++;

    dataStr[idx] = '\0';
    return idx;
}

void atoiWorker( char dataStr[], char results[], int idx)
{
    int i;
    printf( "converting strings to ints\n" );
    for (i = 0; i < idx; i++)
        results[i] = atoi(&dataStr[i]);
}

void tokenize(char dataStr[], char *results[])
{
    int count = 0;
    char delim[] = " ,\t\n"; //found this on msdn, hopefully it's right

    if (results[0] = strtok(dataStr, " \t"))
        count++;

    while (results[count] = strtok(NULL, delim/*" \t"*/))
        count++;
}

void printer(char dataStr[], int idx)
{
    int i;
    printf( "Printing the string\n" );
    for (i = 0; i < idx; i++)
        printf( " %d,", dataStr[i] );
    printf( "\n" );
}
4

2 回答 2

1

像这样修复

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
#include <assert.h>

#define STRING_LENGTH 81
#define MAX_TOKENS 40

void StrInput( char dataStr[]);
void atoiWorker( char *tokens[], int results[], int idx);
void printer ( int results[], int idx);
int tokenize ( char dataStr[], char *results[]);

int main()
{
    int idx;
    char dataStr[STRING_LENGTH];
    char *tokens[MAX_TOKENS];
    int results[MAX_TOKENS];
    StrInput(dataStr);
    idx = tokenize(dataStr, tokens);
    atoiWorker(tokens, results, idx);
    printer(results, idx);
}

void StrInput(char dataStr[])
{
    int idx = 0;
    printf( "please enter your string: " );
    while (idx < (STRING_LENGTH) && ((dataStr[idx] = getchar()) != '\n'))
        idx++;

    dataStr[idx] = '\0';
}

void atoiWorker( char *tokens[], int results[], int idx)
{
    int i;
    printf( "converting strings to ints\n" );
    for (i = 0; i < idx; i++)
        results[i] = atoi(tokens[i]);
}

int tokenize(char dataStr[], char *results[])
{
    int count = 0;
    char delim[] = " ,\t\n"; //found this on msdn, hopefully it's right

    if (results[0] = strtok(dataStr, " \t"))
        count++;

    while (results[count] = strtok(NULL, delim/*" \t"*/))
        count++;
    return count;
}

void printer(int result[], int idx)
{
    int i;
    printf( "Printing the string\n" );
    for (i = 0; i < idx; i++)
        printf( " %d,", result[i] );
    printf( "\n" );
}
于 2013-04-23T00:56:44.653 回答
1

设置后results[]，tokenize()然后将其覆盖在atioWorker().

于 2013-04-23T00:00:51.180 回答