python - 如何在python中禁用堆栈跟踪

Question

我想禁用在引发异常时打印的堆栈跟踪。

Answer 1

每当代码调用该logger.exception方法时，就会自动打印堆栈跟踪。那是因为方法的exc_info参数的默认值.exception是True。

查看源代码：

def exception(msg, *args, exc_info=True, **kwargs):
    """
    Log a message with severity 'ERROR' on the root logger, with exception
    information. If the logger has no handlers, basicConfig() is called to add
    a console handler with a pre-defined format.
    """
    error(msg, *args, exc_info=exc_info, **kwargs)

为了防止这种情况，您可以发送exc_info=False到这样的 .exception方法：

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}", exc_info=False)

虽然这看起来可行，但强制用户在exc_info=False每次使用该方法时都编写是不好的。因此，为了从程序员的肩上分担这个负担，你可以给.exception方法打补丁，让它像这样的常规.error方法：

# somewhere in the start of your program
# money patch the .exception method
logger.exception = logger.error

  try:
      raise Exception("Huston we have a problem!")
  except Exception as ex:
      logger.exception(f"Looks like they have a problem: {ex}")

Answer 2

环顾四周，我发现了以下解决方案/解决方法：

sys.tracebacklimit = 0