8

你好亲爱的同事们，

我有一个 Garden 类，我在其中序列化和反序列化多个 Plant 类对象。序列化正在工作，但如果要将其分配给 mein 静态方法中的调用变量，则反序列化不起作用。

public void searilizePlant(ArrayList<Plant> _plants) {
    try {
        FileOutputStream fileOut = new FileOutputStream(fileName);
        ObjectOutputStream out = new ObjectOutputStream(fileOut);
        for (int i = 0; i < _plants.size(); i++) {
            out.writeObject(_plants.get(i));
        }
        out.close();
        fileOut.close();
    } catch (IOException ex) {
    }
}

反序列化代码：

public ArrayList<Plant> desearilizePlant() {
    ArrayList<Plant> plants = new ArrayList<Plant>();
    Plant _plant = null;
    try {
        ObjectInputStream in = new ObjectInputStream(new FileInputStream(fileName));
        Object object = in.readObject();

       // _plant = (Plant) object;


        // TODO: ITERATE OVER THE WHOLE STREAM
        while (object != null) {
            plants.add((Plant) object);
            object = in.readObject();
        }

        in.close();
    } catch (IOException i) {
        return null;
    } catch (ClassNotFoundException c) {
        System.out.println("Employee class not found");
        return null;
    }
    return plants;
}

我的调用代码：

ArrayList<Plant> plants = new ArrayList<Plant>();
plants.add(plant1);
Garden garden = new Garden();
garden.searilizePlant(plants);

// THIS IS THE PROBLEM HERE
ArrayList<Plant> dp = new ArrayList<Plant>();
dp = garden.desearilizePlant();

编辑
我得到一个空指针异常
@NilsH 的解决方案工作正常，谢谢！

4

3 回答 3

19

如何序列化整个列表呢？无需序列化列表中的每个单独对象。

public void searilizePlant(ArrayList<Plant> _plants) {
    try {
        FileOutputStream fileOut = new FileOutputStream(fileName);
        ObjectOutputStream out = new ObjectOutputStream(fileOut);
        out.writeObject(_plants);
        out.close();
        fileOut.close();
    } catch (IOException ex) {
    }
}

public List<Plant> deserializePlant() {
    List<Plants> plants = null;
    try {
        ObjectInputStream in = new ObjectInputStream(new FileInputStream(fileName));
        plants = in.readObject(); 
        in.close();
    }
    catch(Exception e) {}
    return plants;
}

如果这不能解决您的问题，请发布有关您的错误的更多详细信息。

于 2013-04-22T11:13:36.957 回答
1

反序列化整个对象列表可能并不总是可行的（例如，由于内存问题）。在这种情况下尝试：

    ObjectInputStream in = new ObjectInputStream(new FileInputStream(
            filename));

    while (true) {
        try {
            MyObject o = (MyObject) in.readObject();
            // Do something with the object
        } catch (EOFException e) {
            break;
        }
    }

    in.close();

或者使用 Java SE 7 try-with-resources 语句：

    try (ObjectInputStream in = new ObjectInputStream(new FileInputStream(
            filename))) {
        while (true) {
            MyObject o = (MyObject) in.readObject();
            // Do something with the object
        }
    } catch (EOFException e) {
        return;
    }
于 2014-01-24T21:38:15.683 回答
0

如果将其序列化为数组线性列表，则可以在反序列化时将其转换回数组线性列表——所有其他方法对我来说都失败了： 

import java.io.*;
import java.util.ArrayList;
import java.util.Arrays;

public class Program 
{
    public static void writeToFile(String fileName, Object obj, Boolean appendToFile) throws Exception
    {
        FileOutputStream fs = null;
        ObjectOutputStream os = null;
        try
        {
            fs = new FileOutputStream(fileName);
            os = new ObjectOutputStream(fs);

            //ObjectOutputStream.writeObject(object) inherently writes binary
            os.writeObject(obj); //this does not use .toString() & if you did, the read in would fail
        }
        catch (FileNotFoundException e)
        {
            e.printStackTrace();
        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        finally
        {
            try
            {
                os.close();
                fs.close();
            }
            catch(Exception e)
            {
                //if this fails, it's probably open, so just do nothing
            }
        }
    }


    @SuppressWarnings("unchecked")
    public static ArrayList<Person> readFromFile(String fileName)
    {
        FileInputStream fi = null;
        ObjectInputStream os = null;
        ArrayList<Person> peopleList = null;
        try
        {
            fi = new FileInputStream(fileName);
            os = new ObjectInputStream(fi);
            peopleList = ((ArrayList<Person>)os.readObject());  
        }
        catch (FileNotFoundException e)
        {
            e.printStackTrace();
        }
        catch(EOFException e)
        {                     
            e.printStackTrace();
        }
        catch(ClassNotFoundException e) 
        {
            e.printStackTrace();
        }
        catch (IOException e)
        {
            e.printStackTrace();
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        finally
        {
            try
            {
                os.close();
                fi.close();
            }
            catch(Exception e)
            {
                //if this fails, it's probably open, so just do nothing
            }
        }
        return peopleList;
    }




    public static void main(String[] args) 
    {
        Person[] people = { new Person(1, 39, "Coleson"), new Person(2, 37, "May") };
        ArrayList<Person> peopleList = new ArrayList<Person>(Arrays.asList(people));

        System.out.println("Trying to write serializable object array: ");

        for(Person p : people)
        {
            System.out.println(p);
        }
        System.out.println(" to binary file");

        try
        {
            //writeToFile("output.bin", people, false); //serializes to file either way
            writeToFile("output.bin", peopleList, false); //but only successfully read back in using single cast
        }                                                // peopleList = (ArrayList<Person>)os.readObject();
                                                         // Person[] people = (Person[])os.readObject(); did not work
                                                        // trying to read one at a time did not work either (not even the 1st object) 
        catch (Exception e)
        {
            e.printStackTrace();
        }



        System.out.println("\r\n");




        System.out.println("Trying to read object from file. ");
        ArrayList<Person> foundPeople = null;
        try
        {
            foundPeople = readFromFile("input.bin");
        } 
        catch (Exception e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        if (foundPeople == null)
        {
            System.out.println("got null, hummm...");
        }
        else
        {
            System.out.println("found: ");

            for(int i = 0; i < foundPeople.size(); i++)
            {
                System.out.println(foundPeople.get(i));
            }

            //System.out.println(foundPeople); //implicitly calls .toString()
        }
    }
}
于 2015-05-14T18:20:26.900 回答