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我有一个主图像，用户单击链接可以将其更改为五个不同图像之一。在这种情况下，链接“一”、“二”、“三”、“四”或“五”。

因此，单击链接“三”会将主图像更改为显示第三个图像。

这一切正常，但我正在寻找淡入而不是立即出现的图像。这可以通过快速修改下面的代码来实现吗？

提前谢谢了，

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Image Change Demo</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<script type="text/javascript">
function changeIt(objName)
{
//The image object accessed through its id we mentioned in the DIV block which is going to be visible currently
var obj = document.getElementById(objName);

//An array that hold the IDs of images that we mentioned in their DIV blocks
var objId = new Array();

//Storing the image IDs into the array starts here
objId[0] = "image1";
objId[1] = "image2";
objId[2] = "image3";
objId[3] = "image4";
objId[4] = "image5";
//Storing the image IDs into the array ends here

//A counter variable going to use for iteration
var i;

//A variable that can hold all the other object references other than the object which is going to be visible
var tempObj;

//The following loop does the display of a single image based on its ID. The image whose ID we passed into this function will be the
//only image that is displayed rest of the images will be hidden based on their IDs and that part has been handled by the else part
//of the if statement within this loop.
for(i=0;i<objId.length;i++)
{
    if(objName == objId[i])
    {
        obj.style.display = "block";
        rotate.nu=i;
    }
    else
    {
        tempObj = document.getElementById(objId[i]);
        tempObj.style.display = "none";
    }
}
return;
}

function rotate()
{

//An array that hold the IDs of images that we mentioned in their DIV blocks
var objId = new Array();

//Storing the image IDs into the array starts here
objId[0] = "image1";
objId[1] = "image2";
objId[2] = "image3";
objId[3] = "image4";
objId[4] = "image5";
rotate.nu=rotate.nu||0;
document.getElementById(objId[rotate.nu]).style.display = "none";
rotate.nu=++rotate.nu%objId.length;
document.getElementById(objId[rotate.nu]).style.display = "block";
}

</script>
</head>

<body>
<div id="image1" onmouseup="rotate();" >
<img src="dimming/1.jpg" border="0" alt="one" />
</div>

<div id="image2" style="display:none" onmouseup="rotate();">
<img src="dimming/2.jpg" border="0" alt="two" />
</div>

<div id="image3" style="display:none" onmouseup="rotate();">
<img src="dimming/C.jpg" border="0" alt="three" />
</div>

<div id="image4" style="display:none" onmouseup="rotate();">
<img src="dimming/D.jpg" border="0" alt="four" />
</div>

<div id="image5" style="display:none" onmouseup="rotate();">
<img src="dimming/E.jpg" border="0" alt="five" />
</div>
<br><br>
<a id="one" href="#" onclick="changeIt('image1');">one</a>
<a id="two" href="#" onclick="changeIt('image2');">two</a>
<a id="three" href="#" onclick="changeIt('image3');">three</a>
<a id="four" href="#" onclick="changeIt('image4');">four</a>
<a id="five" href="#" onclick="changeIt('image5');">five</a>
</body>
</html>
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1 回答 1

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如果您正在寻找简单的方法，您可能会使用 jQuery 框架。像这样的用法：

$('.image').fadeIn(1000)
于 2013-04-21T17:36:34.633 回答