java - 如何在循环中的某个点打印“i”的值？

Question

public static void main(String[] args) {
    int largestChain = 0;
    for(int i = 1; i < 1000000; ++i) {
        if(chain(i) > largestChain) {
            largestChain = chain(i);  // Here, how do I print the final value
                                      // of 'i' that respects the rule chain(i)?
        }
    }
    System.out.print(largestChain);
}

例如，如果i = 13, chain(i) = 10，并且largestChain13（从 1 开始）是 10。现在假设我们有一个循环，从 1 到 100，并且largestChain仍然是 10，相同的i = 13。i当循环必须完成其任务（并进入 100）时，我该如何打印？

Answer 1

可能这就是你想要的：

public static void main(String[]args){

    int largestChain = 0;
    int largestIndex = 0;
    for(int i = 1; i < 1000000; ++i){
        if(chain(i) > largestChain){
            largestChain = chain(i); 
            largestIndex = i;
        }
    }
    System.out.print("Largest chain is :"+largestChain);
    System.out.print("Largest chain index is :"+largestIndex);
}

Answer 2

    int largestChain = 0;
    int index =0;
    for(int i = 1; i < 1000000; ++i){
        if(chain(i) > largestChain){
            largestChain = chain(i); //here, how do I print the final value of 'i' that respects the rule chain(i) 
            index = i;
        }
    }
    System.out.print(largestChain + " index  : " + index);