python - 正则表达式字符串和转义引号

Question

如何获得以下两个文本中引号之间的内容？

text_1 = r""" "Some text on \"two\" lines with a backslash escaped\\" \
     + "Another text on \"three\" lines" """

text_2 = r""" "Some text on \"two\" lines with a backslash escaped\\" + "Another text on \"three\" lines" """

对我来说，问题是引号如果被转义应该被忽略，但是反斜杠有可能被转义。

我想获得以下组。

[
    r'Some text on \"two\" lines with a backslash escaped\\',
    r'Another text on \"three\" lines'
]

Answer 1

"(?:\\.|[^"\\])*"

匹配带引号的字符串，包括其中出现的任何转义字符。

解释：

"       # Match a quote.
(?:     # Either match...
 \\.    # an escaped character
|       # or
 [^"\\] # any character except quote or backslash.
)*      # Repeat any number of times.
"       # Match another quote.

Answer 2

匹配除双引号外的所有内容：

import re
text = "Some text on \"two\" lines" + "Another text on \"three\" lines"
print re.findall(r'"([^"]*)"', text)

输出

['two', 'three']

Answer 3

>>> import re
>>> text = "Some text on\n\"two\"lines" + "Another texton\n\"three\"\nlines"
>>> re.findall(r'"(.*)"', text)
["two", "three"]

Answer 4

>>> import re
>>> text_1 = r""" "Some text on \"two\" lines with a backslash escaped\\" \
     + "Another text on \"three\" lines" """
>>> text_2 = r""" "Some text on \"two\" lines with a backslash escaped\\" + "Another text on \"three\" lines" """
>>> re.findall(r'\\"([^"]+)\\"', text_2)
['two', 'three']
>>> re.findall(r'\\"([^"]+)\\"', text_1)
['two', 'three']

也许你想要这个：

re.findall(r'\\"((?:(?<!\\)[^"])+)\\"', text)