c++ - 将文本文件中的数据读入结构数组

Question

我以前见过这个问题，但我找不到可以帮助我解决问题的答案。这里发生了一些事情。这将显示一个菜单，允许用户：

1. 查看费用，
2. 更新费用，或
3. 退出以返回上一个菜单。

此信息保存到应输入和输出的数据文件中。尝试查看文件中的数据时，第一个菜单选项有问题。假设已经有一个C:\danceexpenses.txt包含此信息的数据文件：

DJ
100
Site
100
Food
100
Favors
100
Security
100
Ticket printing
100
Etc.
100
etc.
100

程序不会显示信息。它只为每个提供一个空行。我需要添加一些东西来配置输出吗？

void charges()
{
    //Structures to hold data
    struct Expenses
    {
        string name; 
        double cost;
    };

    int chargesChoice;
    const int CHARGES_MENU_VIEW = 1, CHARGES_MENU_UPDATE = 2, CHARGES_MENU_QUIT = 3;
    const int NUM_EXPENSES = 8; //number of expenses
    Expenses danceExpenses[NUM_EXPENSES]; //array of structures
    int index; //loop counter

    cout << "\nWhat would you like to do?\n\n"
        << "1. View charges\n"
        << "2. Update charges\n"
        << "3. Return to main menu\n"
        << "Enter your choice: ";
    cin >> chargesChoice;

    while (chargesChoice < CHARGES_MENU_VIEW || chargesChoice > CHARGES_MENU_QUIT)
    {
        cout << "\nPlease enter a valid menu choice: ";
        cin >> chargesChoice;       
    }

    switch (chargesChoice)
    {
        case CHARGES_MENU_VIEW: //Display the expenses data
            myFile.open("c:\\danceexpenses.txt", ios::in); //open file
            if (!myFile)
            {
                cout << "Error opening file. Program aborting.\n";
                return;
            }
            char output[100];
            cout << "\nHere are the expected expenses for the dance:\n";
            for (index = 0; index < NUM_EXPENSES; index++)
                cout << danceExpenses[index].name << endl << endl;
            myFile.close(); //close file
            break;
        case CHARGES_MENU_UPDATE:
            //get expense data
            myFile.open("c:\\danceexpenses.txt", ios::out); //open file
            if (!myFile)
            {
                cout << "Error opening file. Program aborting.\n";
                return;
            }
            for (index = 0; index < NUM_EXPENSES; index++)
            {
                cout << "Enter the name of the expense: ";
                cin.ignore();
                getline(cin, danceExpenses[index].name);
                cout << "Enter the expected cost for this expense: ";
                cin >> danceExpenses[index].cost;
            }

            //Write data to file
            for (index = 0; index < NUM_EXPENSES; index++)
            {
                myFile << danceExpenses[index].name << endl;
                myFile << danceExpenses[index].cost << endl;
            }
            myFile.close(); //close file
            break;
        case CHARGES_MENU_QUIT:
            showMenu();
            break;
    }
    charges();
}

Answer 1

如果您的第一个操作是输入 1，则代码应输入：

    case CHARGES_MENU_VIEW: //Display the expenses data
        myFile.open("c:\\danceexpenses.txt", ios::in); //open file
        if (!myFile)
        {
            cout << "Error opening file. Program aborting.\n";
            return;
        }
        char output[100];
        cout << "\nHere are the expected expenses for the dance:\n";
        for (index = 0; index < NUM_EXPENSES; index++)
            cout << danceExpenses[index].name << endl << endl;
        myFile.close(); //close file
        break;

这将打开舞蹈费用文件，但不会从中读取。然后它遍历尚未初始化的费用列表，并关闭输入文件。还有一个未使用的变量output。

在打印出来之前，您需要将数据读入内存。

int num = 0;
while (myFile >> danceexpenses[num].name >> danceexpenses[num].cost)
    num++;

for (index = 0; index < num; index++)
    cout << danceExpenses[index].name << endl << endl;