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将 html 文件作为附件发送的这段代码工作正常。但是在下一个代码片段中，当我将附件更改为图像时，它没有被发送。为什么会这样？

<?php
$file_path = "file.html"; // server path where file is placed
$file_path_type = "text/html"; // File Type
$file_path_name = "newfilename.html"; // this file name will be used at reciever end 

$from = "xyz@gmail.com"; // E-mail address of sender
$to = "abc@gmail.com"; // E-mail address of reciever
$subject = "Please check the Attachment."; // Subject of email
$message = "This is the message body.&lt;br&gt;&lt;br&gt;Thank You!&lt;br&gt;&lt;a href='http://7tech.co.in'&gt;7tech.co.in Team&lt;/a&gt;"; 

$headers = "From: ".$from; 

$file = fopen($file_path,'rb');
$data = fread($file,filesize($file_path));
fclose($file); 

$rand = md5(time());
$mime_boundary = "==Multipart_Boundary_x{$rand}x"; 

$headers .= "\nMIME-Version: 1.0\n" .
"Content-Type: multipart/mixed;\n" .
" boundary=\"{$mime_boundary}\""; 

$message .= "This is a multi-part message in MIME format.\n\n" .
"--{$mime_boundary}\n" .
"Content-Type:text/html; charset=\"iso-8859-1\"\n" .
"Content-Transfer-Encoding: 7bit\n\n" .
$message .= "\n\n"; 

$data = chunk_split(base64_encode($data)); 

$message .= "--{$mime_boundary}\n" .
"Content-Type: {$file_path_type};\n" .
" name=\"{$file_path_name}\"\n" .
"Content-Disposition: attachment;\n" .
" filename=\"{$file_path_name}\"\n" .
"Content-Transfer-Encoding: base64\n\n" .
$data .= "\n\n" .
"--{$mime_boundary}--\n";  

if(@mail($to, $subject, $message, $headers)) {
echo "File send!";

} else {
echo 'Failed';
}
?>

现在，当我将附件更改为图片（即 screenshot.png）时，它无法发送消息。

<?php
    $file_path = "screenshot.png"; // server path where file is placed
    $file_path_type = "image/png"; // File Type
    $file_path_name = "screenshot.png"; // this file name will be used at reciever end 

    $from = "xyz@gmail.com"; // E-mail address of sender
    $to = "abc@gmail.com"; // E-mail address of reciever
    $subject = "Please check the Attachment."; // Subject of email
    $message = "This is the message body.&lt;br&gt;&lt;br&gt;Thank You!&lt;br&gt;&lt;a href='http://7tech.co.in'&gt;7tech.co.in Team&lt;/a&gt;"; 

    $headers = "From: ".$from; 

    $file = fopen($file_path,'rb');
    $data = fread($file,filesize($file_path));
    fclose($file); 

    $rand = md5(time());
    $mime_boundary = "==Multipart_Boundary_x{$rand}x"; 

    $headers .= "\nMIME-Version: 1.0\n" .
    "Content-Type: multipart/mixed;\n" .
    " boundary=\"{$mime_boundary}\""; 

    $message .= "This is a multi-part message in MIME format.\n\n" .
    "--{$mime_boundary}\n" .
    "Content-Type:text/html; charset=\"iso-8859-1\"\n" .
    "Content-Transfer-Encoding: 7bit\n\n" .
    $message .= "\n\n"; 

    $data = chunk_split(base64_encode($data)); 

    $message .= "--{$mime_boundary}\n" .
    "Content-Type: {$file_path_type};\n" .
    " name=\"{$file_path_name}\"\n" .
    "Content-Disposition: attachment;\n" .
    " filename=\"{$file_path_name}\"\n" .
    "Content-Transfer-Encoding: base64\n\n" .
    $data .= "\n\n" .
    "--{$mime_boundary}--\n";  

    if(@mail($to, $subject, $message, $headers)) {
    echo "File send!";

    } else {
    echo 'Failed';
    }
    ?>

你们能指出错误吗？我也尝试在 1-2 个地方更改内容类型，但它不起作用。我错过了什么吗？

4

1 回答 1

1

咨询PhpMailer 与 SwiftMailer？

您当然可以继续使用繁琐的手动邮件构建代码。但是请不要将额外的调试工作卸载给其他人。你的选择，你的问题。

如果您有点聪明，请使用现有解决方案之一，而不是创可贴代码。

于 2013-04-20T18:27:36.540 回答