php - preg_replace 不忽略字符串中的 []

Question

这是我的代码：

$string = "Hello this is my text [readmore] and this is remaining text";
echo preg_replace("[readmore]","",$string);

这是我的预期输出：

Hello this is my text and this is remaining text

这是我的实际输出：

Hello this is my text [] and this is remaining text

问题也很简单，如何获得“[]”？

Answer 1

你需要逃避[& ]。试试下面的正则表达式，

preg_replace("/\[([^\[\]]++|(?R))*+\]/", "", $string);

输出：

Hello this is my text and this is remaining text

键盘演示。

Answer 2

您需要转义括号以在正则表达式中使用。此外，您可能需要查看手册preg_replace，因为您省略了/需要在您的正则表达式周围的内容。

$string = "Hello this is my text [readmore] and this is remaining text";
echo preg_replace("/\[readmore\]/","",$string);

Answer 3

转义 '[' 和 ']' 字符：

这个脚本：

 $string = "Hello this is my text [readmore] and this is remaining text";
 echo preg_replace("[\\[readmore\\] ]","",$string);

这个结果（我测试了这个）：

 Hello this is my text and this is remaining text     

Answer 4

利用str_replace

$string = "Hello this is my text [readmore] and this is remaining text";
echo str_replace("[readmore]","",$string);

输出

Hello this is my text and this is remaining text