0

我正在尝试设置具有以下字段的报告：

在此处输入图像描述

几乎需要报告显示日期，该日期的总记录（所以我按日期分组）然后按小时计算 12 小时工作日（从上午 8 点到晚上 8 点）我需要计算什么时候在这些时间内存在记录。经过一些头脑风暴和头脑放屁后，我想为什么不使用一个案例。这是我尝试过的：

 SELECT 
        DATE_FORMAT(signintime, '%b %d, %Y') Date, 
        COUNT(session_id) as Total,
        SUM(CASE WHEN HOUR(signintime) > 08 AND HOUR(signintime) < 09 THEN 1 ELSE 0 END) '8AM-9PM',
        SUM(CASE WHEN HOUR(signintime) > 09 AND HOUR(signintime) < 10 THEN 1 ELSE 0 END) '9AM-10AM',
        SUM(CASE WHEN HOUR(signintime) > 10 AND HOUR(signintime) < 11 THEN 1 ELSE 0 END) '10AM-11AM',
        SUM(CASE WHEN HOUR(signintime) > 11 AND HOUR(signintime) < 12 THEN 1 ELSE 0 END) '11AM-12PM',
        SUM(CASE WHEN HOUR(signintime) > 12 AND HOUR(signintime) < 13 THEN 1 ELSE 0 END) '12PM-1PM',
        SUM(CASE WHEN HOUR(signintime) > 13 AND HOUR(signintime) < 14 THEN 1 ELSE 0 END) '1PM-2PM',
        SUM(CASE WHEN HOUR(signintime) > 14 AND HOUR(signintime) < 15 THEN 1 ELSE 0 END) '2PM-3PM',
        SUM(CASE WHEN HOUR(signintime) > 15 AND HOUR(signintime) < 16 THEN 1 ELSE 0 END) '3PM-4PM',
        SUM(CASE WHEN HOUR(signintime) > 16 AND HOUR(signintime) < 17 THEN 1 ELSE 0 END) '4PM-5PM',
        SUM(CASE WHEN HOUR(signintime) > 17 AND HOUR(signintime) < 18 THEN 1 ELSE 0 END) '5PM-6PM',
        SUM(CASE WHEN HOUR(signintime) > 18 AND HOUR(signintime) < 19 THEN 1 ELSE 0 END) '6PM-7PM',
        SUM(CASE WHEN HOUR(signintime) > 19 AND HOUR(signintime) < 20 THEN 1 ELSE 0 END) '7PM-8PM'
 FROM session 
 WHERE session.status = '3'
 GROUP by HOUR(signintime), Date;

如果您注意到上面的图片，那么现在一整天（2013 年 4 月 19 日）的总数是 1，如果您注意到时间（上午 8 点到晚上 8 点）它们都被清零了。我不确定在哪里转向/在哪里调试它。希望用另一双眼睛，我可以继续前进。

问候。

4

1 回答 1

2

您不需要同时使用>and<来获得结果，您只需检查hour值：

select DATE_FORMAT(signintime, '%b %d, %Y') Date, 
  count(session_id) as Total,
  SUM(CASE WHEN HOUR(signintime) = 08 THEN 1 ELSE 0 END) '8AM-9AM',
  SUM(CASE WHEN HOUR(signintime) = 09 THEN 1 ELSE 0 END) '9AM-10AM',
  SUM(CASE WHEN HOUR(signintime) = 10 THEN 1 ELSE 0 END) '10AM-11AM',
  SUM(CASE WHEN HOUR(signintime) = 11 THEN 1 ELSE 0 END) '11AM-12PM',
  SUM(CASE WHEN HOUR(signintime) = 12 THEN 1 ELSE 0 END) '12PM-1PM',
  SUM(CASE WHEN HOUR(signintime) = 13 THEN 1 ELSE 0 END) '1PM-2PM',
  SUM(CASE WHEN HOUR(signintime) = 14 THEN 1 ELSE 0 END) '2PM-3PM',
  SUM(CASE WHEN HOUR(signintime) = 15 THEN 1 ELSE 0 END) '3PM-4PM',
  SUM(CASE WHEN HOUR(signintime) = 16 THEN 1 ELSE 0 END) '4PM-5PM',
  SUM(CASE WHEN HOUR(signintime) = 17 THEN 1 ELSE 0 END) '5PM-6PM',
  SUM(CASE WHEN HOUR(signintime) = 18 THEN 1 ELSE 0 END) '6PM-7PM',
  SUM(CASE WHEN HOUR(signintime) = 19 THEN 1 ELSE 0 END) '7PM-8PM'
from session
WHERE session.status = '3'
group by DATE_FORMAT(signintime, '%b %d, %Y');

请参阅带有演示的 SQL Fiddle

于 2013-04-20T00:31:52.460 回答