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WS-I 概要文件中不允许方法重载。通常的技巧似乎是添加@WebMethod(operationName="...")注释。如果我这样做，我会得到一个 ClassCastException。

最小的例子如下。

界面：

package org.example.test;

import javax.jws.WebMethod;
import javax.jws.WebService;

@WebService(name = "service", targetNamespace = "http://www.example.org/test")
public interface IThing {

    @WebMethod(operationName = "f1")
    public String f(String s);

    @WebMethod(operationName = "f2")
    public String f(Integer i);
}

执行：

package org.example.test;

import javax.jws.WebMethod;
import javax.jws.WebService;

@WebService(endpointInterface = "org.example.test.IThing", targetNamespace = "http://www.example.org/test", portName = "ThingPort", serviceName = "service")
public class Thing implements IThing {

    @Override
    @WebMethod(operationName = "f1")
    public String f(String s) {
        return "f1";
    }

    @Override
    @WebMethod(operationName = "f2")
    public String f(Integer i) {
        return "f2";
    }

}

JUnit 测试用例：

package org.example.test;

import java.net.URL;

import javax.xml.namespace.QName;
import javax.xml.ws.Service;

import org.junit.Test;

public class TestThing {

    @Test
    public void testThing() throws Exception {
        URL urlURL = new URL("http://localhost:8080/wstest/SOAP");
        QName qname = new QName("http://www.example.org/test", "service");
        Service service = Service.create(urlURL, qname);
        IThing thing = service.getPort(IThing.class);
        thing.f("s");
        thing.f(1);
    }
}

使用的 JAX-WS 实现：

    compile group:'com.sun.xml.ws', name:'jaxws-rt', version:'2.2.7', transitive:true

轨迹轨迹：

java.lang.ClassCastException: java.lang.Integer cannot be cast to java.lang.String
    at org.example.test.jaxws.F$JaxbAccessorF_arg0.set(FieldAccessor_Ref.java:60)
    at com.sun.xml.bind.v2.runtime.reflect.Accessor.setUnadapted(Accessor.java:166)
    at com.sun.xml.bind.v2.runtime.JAXBContextImpl$6.set(JAXBContextImpl.java:980)
    at com.sun.xml.ws.db.glassfish.RawAccessorWrapper.set(RawAccessorWrapper.java:73)
    at com.sun.xml.ws.client.sei.BodyBuilder$DocLit.build(BodyBuilder.java:264)
    at com.sun.xml.ws.client.sei.BodyBuilder$JAXB.createMessage(BodyBuilder.java:103)
    at com.sun.xml.ws.client.sei.StubHandler.createRequestPacket(StubHandler.java:231)
    at com.sun.xml.ws.db.DatabindingImpl.serializeRequest(DatabindingImpl.java:195)
    at com.sun.xml.ws.db.DatabindingImpl.serializeRequest(DatabindingImpl.java:257)
    at com.sun.xml.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:117)
    at com.sun.xml.ws.client.sei.SyncMethodHandler.invoke(SyncMethodHandler.java:102)
    at com.sun.xml.ws.client.sei.SEIStub.invoke(SEIStub.java:154)
    at com.sun.proxy.$Proxy31.f(Unknown Source)
    at org.example.test.TestThing.testThing(TestThing.java:19)

运行环境是Tomcat7。

我假设我也没有被迫重命名 Java 方法。我是吗？

包含 Eclipse 项目的 zip 可在http://ge.tt/1JrLxFh/v/0获得

4

1 回答 1

1

您还需要确保区分参数。否则，模式会将相同的类型与两种方法的参数相关联，从而有效地破坏您的重载意图。

@Override  
@WebMethod(operationName = "f2")  
@ResponseWrapper(className = "f2Response")  
@RequestWrapper(className = "f2")   
public String f(Integer i) {  
        return "f2";  
}
于 2014-01-19T17:43:38.590 回答