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我在使用 SQL Server 时遇到以下查询问题。 

SELECT  
        emp_id= CASE employee_id
        WHEN ''
            THEN RTRIM(last_name) + '_' + RTRIM(first_name)
            + '_' + RTRIM(gender) + '_'
            + RTRIM(race_ethnicity_code) + '_'
            + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_'
            + RTRIM(assignment_code)
            ELSE employee_id
            END , 
        last_name, first_name, 
        assign_perc, 
            assignment_num,
        CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) AS salary,
        total_salary
FROM employee 
ORDER BY last_name, first_name, district_name

我的脚本是一个简单的列提取，当 emp_id 为空时，通过 case 语句为它创建一个唯一键。我遇到的问题是，当该人有多项任务时，将 assign_perc 与 total_Salary 相乘，而当该销售人员仅列出一次时，则获得最高薪水。例如 - 我的预期结果：

在此处输入图像描述

John Smith 只是一名兼职工作人员，他的一项任务只列出一次，因此他的 assign_perc 将小于 1，但我仍然需要最高工资而不是总工资 (assign_perc*total_salary)。谢谢您的帮助。

4

1 回答 1

1

如上所述，这非常混乱，因为您需要使用 CASE 语句来确定虚拟employee_id. 如果您可以将此 CASE 语句重构为 udf，或者将结果存储在表中，那会简单得多！

为了澄清这将要做什么 - 您希望将表连接到employee包含每个员工计数的表上。计数表如下所示：

SELECT employee_id, COUNT(*) AS employee_count
FROM employee
GROUP BY employee_id

将它们连接在一起看起来像这样：

SELECT ...
FROM employee
JOIN (SELECT employee_id, COUNT(*) AS employee_count
      FROM employee
      GROUP BY employee_id) ec
ON employee.employee_id = ec.employee_id

您计算的薪水现在将变为：

        CASE 
            WHEN ec.employee_count > 1 
                THEN CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) 
            ELSE total_salary 
        END AS salary,

下面是用怪异的 CASE 语句代替“employee_id”的完整查询：

SELECT  
        CASE employee.employee_id
        WHEN ''
            THEN RTRIM(last_name) + '_' + RTRIM(first_name)
            + '_' + RTRIM(gender) + '_'
            + RTRIM(race_ethnicity_code) + '_'
            + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_'
            + RTRIM(assignment_code)
            ELSE employee.employee_id
            END AS emp_id, 
        last_name, first_name, 
        assign_perc, 
        assignment_num,
        CASE 
            WHEN ec.employee_count > 1 
                THEN CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) 
            ELSE total_salary 
        END AS salary,
        total_salary
FROM employee
JOIN (SELECT CASE employee.employee_id
        WHEN ''
            THEN RTRIM(last_name) + '_' + RTRIM(first_name)
            + '_' + RTRIM(gender) + '_'
            + RTRIM(race_ethnicity_code) + '_'
            + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_'
            + RTRIM(assignment_code)
            ELSE employee.employee_id
            END AS employee_id, COUNT(*) employee_count 
      FROM employee
      GROUP BY CASE employee.employee_id
        WHEN ''
            THEN RTRIM(last_name) + '_' + RTRIM(first_name)
            + '_' + RTRIM(gender) + '_'
            + RTRIM(race_ethnicity_code) + '_'
            + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_'
            + RTRIM(assignment_code)
            ELSE employee.employee_id
            END) ec 
  ON CASE employee.employee_id
        WHEN ''
            THEN RTRIM(last_name) + '_' + RTRIM(first_name)
            + '_' + RTRIM(gender) + '_'
            + RTRIM(race_ethnicity_code) + '_'
            + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_'
            + RTRIM(assignment_code)
            ELSE employee.employee_id
            END = ec.employee_id
ORDER BY last_name, first_name, district_name
于 2013-04-18T15:41:27.093 回答