105

我需要检查一个date- 格式的字符串dd/mm/yyyy- 是否位于具有相同格式的其他两个日期之间dd/mm/yyyy

我试过这个，但它不起作用：

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "02/07/2013";

var from = Date.parse(dateFrom);
var to   = Date.parse(dateTo);
var check = Date.parse(dateCheck );

if((check <= to && check >= from))      
    alert("date contained");

我使用调试器并检查，toandfrom变量有isNaN值。你可以帮帮我吗？

4

11 回答 11

124

Date.parsemm/dd/yyyy不支持格式 dd/mm/yyyy。对于后者，要么使用像 moment.js 这样的库，要么执行如下所示的操作

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "02/07/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]);
var check = new Date(c[2], parseInt(c[1])-1, c[0]);

console.log(check > from && check < to)
于 2013-04-18T10:36:37.747 回答
67

不是直接比较日期，而是比较日期的 getTime() 值。getTime() 函数以整数形式返回自 1970 年 1 月 1 日以来的毫秒数——应该很容易确定一个整数是否介于其他两个整数之间。

就像是

if((check.getTime() <= to.getTime() && check.getTime() >= from.getTime()))      alert("date contained");
于 2013-04-18T10:26:04.100 回答
21

试试下面的内容。它会帮助你...

小提琴：http: //jsfiddle.net/RYh7U/146/

脚本 ：

if(dateCheck("02/05/2013","02/09/2013","02/07/2013"))
    alert("Availed");
else
    alert("Not Availed");

function dateCheck(from,to,check) {

    var fDate,lDate,cDate;
    fDate = Date.parse(from);
    lDate = Date.parse(to);
    cDate = Date.parse(check);

    if((cDate <= lDate && cDate >= fDate)) {
        return true;
    }
    return false;
}
于 2013-04-18T10:46:56.313 回答
11

有 50 票的答案不检查日期，只检查几个月。这个答案是不正确的。下面的代码有效。

var dateFrom = "01/08/2017";
var dateTo = "01/10/2017";
var dateCheck = "05/09/2017";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1);  // -1 because months are from 0 to 11
var to   = new Date(d2);
var check = new Date(c);

alert(check > from && check < to);

这是另一个答案中发布的代码，我已经更改了日期，这就是我注意到它不起作用的原因

var dateFrom = "02/05/2013";
var dateTo = "02/09/2013";
var dateCheck = "07/07/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");
var c = dateCheck.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]);
var check = new Date(c[2], parseInt(c[1])-1, c[0]);


alert(check > from && check < to);
于 2017-05-05T21:55:19.850 回答
4

基于接受的答案的简化方法。

就我而言，我需要检查当前日期（今天）是否在其他两个日期的范围内，因此使用 newDate() 而不是硬编码值，但您可以了解如何使用硬编码日期。


var currentDate = new Date().toJSON().slice(0,10);
var from = new Date('2020/01/01');
var to   = new Date('2020/01/31');
var check = new Date(currentDate);

console.log(check > from && check < to);
于 2019-12-24T13:59:04.613 回答
3

我创建了自定义函数来验证给定日期是否在两个日期之间。

var getvalidDate = function(d){ return new Date(d) }

function validateDateBetweenTwoDates(fromDate,toDate,givenDate){
    return getvalidDate(givenDate) <= getvalidDate(toDate) && getvalidDate(givenDate) >= getvalidDate(fromDate);
}
于 2019-08-11T19:15:42.040 回答
0

试试这个：

HTML

<div id="eventCheck"></div>

JAVASCRIPT

// ----------------------------------------------------//
// Todays date
var today = new Date();
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();

// Add Zero if it number is between 0-9
if(dd<10) {
    dd = '0'+dd;
}
if(mm<10) {
    mm = '0'+mm;
}

var today = yyyy + '' + mm + '' + dd ;


// ----------------------------------------------------//
// Day of event
var endDay = 15; // day 15
var endMonth = 01; // month 01 (January)
var endYear = 2017; // year 2017

// Add Zero if it number is between 0-9
if(endDay<10) {
    endDay = '0'+endDay;
} 
if(endMonth<10) {
    endMonth = '0'+endMonth;
}

// eventDay - date of the event
var eventDay = endYear + '/' + endMonth + '/' + endDay;
// ----------------------------------------------------//



// ----------------------------------------------------//
// check if eventDay has been or not
if ( eventDay < today ) {
    document.getElementById('eventCheck').innerHTML += 'Date has passed (event is over)';  // true
} else {
    document.getElementById('eventCheck').innerHTML += 'Date has not passed (upcoming event)'; // false
}

小提琴： https ://jsfiddle.net/zm75cq2a/

于 2017-10-19T09:35:09.053 回答
0

这是用 typescript 编写的 Date Prototype 方法：

Date.prototype.isBetween = isBetween;
interface Date { isBetween: typeof isBetween }
function isBetween(minDate: Date, maxDate: Date): boolean {
  if (!this.getTime) throw new Error('isBetween() was called on a non Date object');
  return !minDate ? true : this.getTime() >= minDate.getTime()
    && !maxDate ? true : this.getTime() <= maxDate.getTime();
};
于 2018-09-26T01:07:10.057 回答
0

我做了与@Diode相同的事情，第一个答案，但我用一系列日期制作了条件，我希望这个例子对某人有用

例如（与日期数组示例相同的代码）

var dateFrom = "02/06/2013";
var dateTo = "02/09/2013";

var d1 = dateFrom.split("/");
var d2 = dateTo.split("/");

var from = new Date(d1[2], parseInt(d1[1])-1, d1[0]);  // -1 because months are from 0 to 11
var to   = new Date(d2[2], parseInt(d2[1])-1, d2[0]); 



var dates= ["02/06/2013", "02/07/2013", "02/08/2013", "02/09/2013", "02/07/2013", "02/10/2013", "02/011/2013"];

dates.forEach(element => {
   let parts = element.split("/");
   let date= new Date(parts[2], parseInt(parts[1]) - 1, parts[0]);
        if (date >= from && date < to) {
           console.log('dates in range', date);
        }
})

于 2019-02-09T22:39:11.450 回答
0

例如，假设您的日期即将到来，并且您需要安装 momentjs 以获得提前日期功能。

let cmpDate = Thu Aug 27 2020 00:00:00 GMT+0530 (India Standard Time)

    let format = "MM/DD/YYYY";
    let startDate: any = moment().format(format);
    let endDate: any = moment().add(30, "days").format(format);
    let compareDate: any = moment(cmpDate).format(format);
    var startDate1 = startDate.split("/");
    var startDate2 = endDate.split("/");
    var compareDate1 = compareDate.split("/");

    var fromDate = new Date(startDate1[2], parseInt(startDate1[1]) - 1, startDate1[0]);
    var toDate = new Date(startDate2[2], parseInt(startDate2[1]) - 1, startDate2[0]);
    var checkDate = new Date(compareDate1[2], parseInt(compareDate1[1]) - 1, compareDate1[0]);

    if (checkDate > fromDate && checkDate < toDate) {
      ... condition works between current date to next 30 days
    }
于 2020-10-23T05:38:54.757 回答
-1

试试这个

var gdate='01-05-2014';
        date =Date.parse(gdate.split('-')[1]+'-'+gdate.split('-')[0]+'-'+gdate.split('-')[2]);
        if(parseInt(date) < parseInt(Date.now()))
        {
            alert('small');
        }else{
            alert('big');
        }

小提琴

于 2014-05-09T11:54:31.203 回答