php - 获取重叠像素数PHP

Question

如果我有它们的 X、Y 坐标和它们的高度/宽度，那么在 PHP 中获取两个矩形之间重叠像素数的最短方法是什么？这是一个最佳实践问题，因为我目前正在使用错误/凌乱的 if 语句集合来做这件事。

编辑：这是我目前正在尝试解决的问题：

echo overlapping(1,1,5,5,4,4,6,6).PHP_EOL;
echo overlapping(0,0,29,21,30,20,40,50).PHP_EOL;
function overlapping($x1,$y1,$w1,$h1,$x2,$y2,$w2,$h2){
$wover = abs($x1+($w1/2)  - ($x2+($w2/2))) - ($w1/2)+ ($w2/2);
$hover = abs($y1+($h1/2)  - ($y2+($h2/2))) - ($h1/2)+ ($h2/2);
return $wover*$hover;
}

Answer 1

echo overlapping(0,-1,10,20,30,20,40,50);

function overlapping($x1,$y1,$w1,$h1,$x2,$y2,$w2,$h2){

$wover = abs($x1+($w1/2)  - ($x2+($w2/2))) > ($w1/2)+ ($w2/2)?0:1;

$hover = abs($y1+($h1/2)  - ($y2+($h2/2))) > ($h1/2)+ ($h2/2)?0:1;

if($hover && $wover ){
return 'over';

}
return 'not';

}

http://sandbox.onlinephpfunctions.com/code/1ea506fd72f827965d7241d520789a833b34dff5