2

我正在使用 ksoap2-android-assembly-3.0.0-jar-with-dependencies.jar

我正在做一个需要以下肥皂请求的项目：

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:mod="http://www.tmforum.org/xml/tip/model" xmlns:cust="http://www.tmforum.org/xml/tip/customer/cust">
   <soapenv:Header/>
   <soapenv:Body>
      <mod:listProblemsRequest>
         <!--Optional:-->
         <mod:customer>

            <cust:iD >1100000677</cust:iD>
         </mod:customer>


      </mod:listProblemsRequest>
   </soapenv:Body>
</soapenv:Envelope>

但使用 KSOAP2 我能够生成以下请求：

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
<v:Header />
   <v:Body>
      <retrieveCustomerProfileRequest xmlns="http://www.tmforum.org/xml/tip/model">
           <n0:customer xmlns:n0="http://www.tmforum.org/xml/tip/model">
               <n1:iD i:type="d:string" xmlns:n1="http://www.tmforum.org/xml/tip/customer      /cust">1100000990</n1:iD> 
   </n0:customer>
   </retrieveCustomerProfileRequest>
  </v:Body>
</v:Envelope>

如何i:type="d:string"从 SOAP 请求中删除。

请提出可以在 KSOAP2 的源代码中完成的解决方案或任何解决方法，以便我能够生成适当的请求。

4

3 回答 3

2

我在 ksoap 中找到了解决问题的方法：

1. Download the source code of Ksoap2.jar.
2.open up Transport .java and edit its :

    protected byte[] createRequestData(SoapEnvelope envelope, String encoding)
                throws IOException  

Method.

3.i edited it as follows:


protected byte[] createRequestData(SoapEnvelope envelope, String encoding)
            throws IOException {
        ByteArrayOutputStream bos = new ByteArrayOutputStream(bufferLength);
        byte result[] = null;
        bos.write(xmlVersionTag.getBytes());
        XmlSerializer xw = new KXmlSerializer();
        xw.setOutput(bos, encoding);
        envelope.write(xw);
        xw.flush();
        bos.write('\r');
        bos.write('\n');
        bos.flush();
        result = bos.toByteArray();
        xw = null;
        bos = null;


        String requestObject = new String(result);
        String pattern = "i:type=\"d:string\"";

        String resultString="";

        System.out.println("==earlier String==" + requestObject);
        if (requestObject.contains(pattern)) {

            System.out.println("==is it here ");
            resultString=requestObject.replace(pattern, "");

}

4.compile this class using classpath of ksoap2.jar
5.extract the ksoap2.jar and remove existing transport.class from it.
6.Add newly compiled .class file and make a new jar.
7.import the jar in your project.
Problem solved..
于 2013-04-22T12:10:19.787 回答
0

确保您已设置这些soap信封属性：

    soapEnvelope.implicitTypes = true;
    soapEnvelope.dotNet = true;

在getPropertyInfo返回字段的属性信息时，请确保您设置了正确的类型，例如：

    info.type = field.getClass();
于 2014-01-28T17:15:23.243 回答
0

你在哪里创作

SoapSerializationEnvelope sEnvelop;

只需分配sEnvelop.implicitTypes = true;

它不会创建"i:type="d:string"" or "i:type="d:long""内部数据类型标签，并且 Web 服务可以成功执行

于 2017-01-12T14:00:08.333 回答