问题与说明
您好，我刚刚编写了一个function首先checking if account exists in database使用该名称的代码，然后如果数据库中存在带有该输入电子邮件的电子邮件。
如果没有，return true + insert data.
但是在这种情况下nothing happens on submit，它只显示表单，但不插入数据..它有什么问题？
function createAccount($name, $password, $email)
{
global $pdo;
$check_in = $pdo->prepare("SELECT * FROM users WHERE user_name = :username LIMIT 1");
$check_in->execute( array(':username' => $name) );
if (!$check_in->rowCount())
{
$check_in = email_exists($email);
if ($check_in === false)
{
$insert_in = $pdo->prepare
("
INSERT INTO
users
(user_name, user_password, user_email)
VALUES
(:name, :password, :email)
");
$insert_in->execute( array
(
':name' => $name,
':password' => $password,
':email' => $email
));
return true;
}
else
{
return 'exists';
}
}
else
{
return 'user_in_use';
}
}
function email_exists($email)
{
global $pdo;
$check = $pdo->prepare("SELECT * FROM users WHERE user_email = :email LIMIT 1");
$check->execute( array(':email' => $email) );
if ($check->rowCount())
{
return true;
}
else
{
return false;
}
}
这就是我组成寄存器的方式：
# Creating shortcuts
if (isset($_POST['username']) && isset($_POST['password']) && isset($_POST['email']))
{
$name = $_POST['username'];
$password = $_POST['password'];
$email = $_POST['email'];
}
# Creating errors array
$errors = array();
if (isset($_POST['submit']))
{
$check_in = createAccount($name, $password, $email);
if ($check_in === true)
{
echo 'Created account sucessfully!';
}
else if ($check_in == 'already_in_use')
{
echo 'Could not create account because name already in use..';
}
else if($check_in == 'exists')
{
echo 'Email already in use..';
}
}
问题：
这段代码有什么问题&我该如何解决？我完全没有错误。它只是不会将任何数据插入数据库。
是的，PDO 连接和语句是正确的，因为登录完美。非常感谢！
编辑！
if ($check_in === true)
{
echo 'Created account sucessfully!';
}
else if ($check_in == 'already_in_use')
{
echo 'Could not create account because name already in use..';
}
else if($check_in == 'exists')
{
echo 'Email already in use..';
} else {
echo 'Error is there...';
}
它正在回显“那里有错误...” apon submit！