2

以下是我试图回答的提示：

显示该经理的经理编号和最低薪员工的工资（仅） - 适当标记。不包括经理未知的员工的工资。排除此处的任何组，最低工资低于 1000 美元。首先列出最低工资。

以下是我的 EMPLOYEES 表：

create table EMPLOYEES
    (EmpID    char(4)         unique Not null,
     Ename    varchar(10),
     Job      varchar(9),
     MGR      char(4),
     Hiredate date,
     Salary   decimal(7,2),
     Comm     decimal(7,2),
     DeptNo   char(2)         not null,
         Primary key(EmpID),
         Foreign key(DeptNo) REFERENCES DEPARTMENTS(DeptNo));


insert into EMPLOYEES values (7839,'King','President',null,'17-Nov-11',5000,null,10);
insert into EMPLOYEES values (7698,'Blake','Manager',7839,'01-May-11',2850,null,30);
insert into EMPLOYEES values (7782,'Clark','Manager',7839,'02-Jun-11',2450,null,10);
insert into EMPLOYEES values (7566,'Jones','Manager',7839,'02-Apr-11',2975,null,20);
insert into EMPLOYEES values (7654,'Martin','Salesman',7698,'28-Feb-12',1250,1400,30);
insert into EMPLOYEES values (7499,'Allen','Salesman',7698,'20-Feb-11',1600,300,30);
insert into EMPLOYEES values (7844,'Turner','Salesman',7698,'08-Sep-11',1500,0,30);
insert into EMPLOYEES values (7900,'James','Clerk',7698,'22-Feb-12',950,null,30);
insert into EMPLOYEES values (7521,'Ward','Salesman',7698,'22-Feb-12',1250,500,30);
insert into EMPLOYEES values (7902,'Ford','Analyst',7566,'03-Dec-11',3000,null,20);
insert into EMPLOYEES values (7369,'Smith','Clerk',7902,'17-Dec-10',800,null,20);
insert into EMPLOYEES values (7788,'Scott','Analyst',7566,'09-Dec-12',3000,null,20);
insert into EMPLOYEES values (7876,'Adams','Clerk',7788,'12-Jan-10',1100,null,20);
insert into EMPLOYEES values (7934,'Miller','Clerk',7782,'23-Jan-12',1300,null,10);

以下是我的查询：

select empid, salary
from employees
where salary in
(select MIN(salary)
from employees
where empid in
(select empid
from EMPLOYEES
where JOB != 'manager'))
order by Salary asc;

结果只是除了经理之外薪水最低的人。我需要每位经理薪酬最低的员工，包括总统领导下薪酬最低的经理。

4

2 回答 2

2 
select empid, salary
from employees
where salary in
(select MIN(salary)
from employees
where empid in
(select empid
from EMPLOYEES
where JOB != 'manager'
 group by EmpID
 )
 and
 JOB != 'manager' and MGR is not null
 group by mgr
 )
order by Salary asc;
于 2013-04-17T19:03:43.547 回答
0

尝试这个：

select MGR, MIN(salary)
from EMPLOYEES e
where Salary >= 1000 and MGR is not null
group by mgr
order by MIN(salary)

也许：

select MGR, MIN(salary)
from EMPLOYEES e
where  MGR is not null
group by mgr
having min(salary) >= 1000
order by MIN(salary)

“排除这里的任何团体，最低工资低于 1000 美元”这句话我不清楚。

于 2013-04-17T19:08:42.007 回答