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根据多个键对字典列表进行排序并同时从输出中删除一些字典的最佳（时间）方法是什么？

我希望输出是所有字典的列表，其中"protected":0并按任意数量的其他键排序。

数据

[{"raffle_id":"81","created":"2013-01-07 19:47:57","instant":"1","protected":0,"expire":"never","ticket_price":"0.00050000",
"tickets_total":"10","tickets_sold":"1","my_tickets_count":"1"},
{"raffle_id":"83","created":"2013-01-07 19:49:20","instant":"0","protected":1,"expire":"4d 23h 59m","ticket_price":"0.01000000",
"tickets_total":"50","tickets_sold":"0","my_tickets_count":"0"}]

当前方法

raffle_list = [raffle for raffle in raffle_list if raffle("protected") == "0"]

sorted_raffles = sorted(raffles_list, key = operator.itemgetter("ticket_price", "tickets_sold", "my_tickets_count", "tickets_total"))
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1 回答 1

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我只能建议制作raffle_list一个生成器，但这可能/可能不会更快，具体取决于可用的数据和内存。例如。list comps 对于小型数据集更快，但生成器避免在内存中制作副本，这可能会提高大型数据集的速度，因为sorted也会制作副本：

(raffle for raffle in raffle_list if raffle("protected") == "0")
于 2013-04-17T09:24:30.573 回答