php - 如何将两个选项值传递给 PHP

Question

下面是我目前拥有的代码，它正在努力传递week_num. 我session_start()用来在页面之间传递我的变量。

print'<form action="changeplayer_2.php" method="post">';

print"<select name='Week_select'> <br>";

while ($wrow=mysql_fetch_array($wresult)){ 
     print '<option value="'.$wrow['week_num'].'">'.'week '.$wrow['week_num'].' 
     '.$wrow['week_name'].'</option><br>\n';    
}

print "</select><br><br>";

我很好奇的是我是否也可以week_name转到下一页。请记住，我仍然是初学者，所以如果您能告诉我有关修复工作的原因/方式的任何信息，我将不胜感激。

我努力了

print '<option value="'.$wrow['week_num,week_name'].'">'.'week '.$wrow['week_num'].'     '.$wrow['week_name'].'</option><br>\n';

和

print '<option value="'.$wrow['week_num','week_name'].'">'.'week '.$wrow['week_num'].'     '.$wrow['week_name'].'</option><br>\n';

两者都会产生错误

Answer 1

试试这个串联：

print '<option value="'.$wrow['week_num'].'_'.$wrow['week_name'].'">'.'week '.$wrow['week_num'].'     '.$wrow['week_name'].'</option><br>\n';