python - startswith() 在我的字符串前面找不到'//'

Question

我有一个非常简单的 python 脚本，它读入一个文件，并逐行解析它。

它似乎无法识别我行首的“//”。如果我将其更改为在行首查找“#”，它也找不到这些行。我只是误解了这一点吗？

line = fIn.readline()

while line:
    print "line is", line
    line = line.strip()
    if line.startswith('//'):
        print "winner"
    line = fIn.readline()

我正在阅读的文件如下所示：

// Feedback
"Feedback" = "Feedback";

// New strings
"File URL not reachable." = "File URL not reachable.";

打印出来的调试行看起来很合适：

line is // Feedback

line is "Feedback" = "Feedback";

line is 

line is // New strings

line is "File URL not reachable." = "File URL not reachable.";

line is 

Answer 1

更好的版本：

with open("abc") as f:
    for line in f:
        line=line.strip()
        if line and line.startswith("//"):
            print "line is",line
            print "winner"
            print next(f)
   ....:             

输出：

line is // Feedback
winner
"Feedback" = "Feedback";

line is // New strings
winner
"File URL not reachable." = "File URL not reachable.";

Answer 2

您只阅读文本文件的一行。除了你在最后一行有错误的缩进之外，它似乎有效。在确保line = fIn.readline()每次迭代都执行之后尝试运行您的程序（将其向左移动一个块）。

这是修复那条线后得到的结果，这是所需的输出吗？

line is // Feedback

winner
line is "Feedback" = "Feedback";

line is  

line is // New strings

winner
line is "File URL not reachable." = "File URL not reachable.";

编辑：这对你有用吗？

for line in open("yourfile.txt").readlines():
    print "line is", line
    line = line.strip()
    if line.startswith('//'):
        print "winner"

Answer 3

尝试这个

for line in fIn:
    print "line is", line
    line = line.strip()
    if line[0:2]=='//':
        print "winner"
        line = fIn.readline()