4

我在这样做时遇到了很大的问题，所以我再次来寻求帮助。

我有这个庞大的文件，其中包含尼尔森的所有 DMA，我需要用 php 以某种方式解析每个文件并从中获取数据和坐标，但它们必须以这种格式输出

{"type": "FeatureCollection", "features": [
{
    "type": "Feature",
    "id": "",
    "properties": {
        "dma": "514",
        "name": "Buffalo, NY"
    },
    "geometry": {
        "type": "Polygon",
        "coordinates": [
            [
                [-79.761951, 42.269861],
                [-79.14959, 42.553193],
                [-79.048361, 42.691959],
                [-78.853455, 42.783961],
                [-78.943961, 42.978357],
                [-78.881611, 43.02363],
                [-78.880756, 43.02955],
                [-78.890068, 43.045268],
                [-78.946342, 43.072051],
                [-79.06977, 43.085841],
                [-79.06467, 43.262754],
                [-78.520257, 43.372277],
                [-77.994839, 43.36526],
                [-77.997291, 43.132981],
                [-77.905934, 43.133562],
                [-77.951044, 43.039544],
                [-77.904562, 43.023492],
                [-77.95633, 42.667882],
                [-78.060469, 42.532888],
                [-77.722965, 42.471217],
                [-77.749931, 41.998782],
                [-77.609815, 41.999367],
                [-77.59813, 41.478577],
                [-78.050728, 41.475103],
                [-78.203422, 41.618157],
                [-78.956057, 41.623863],
                [-78.918856, 41.998119],
                [-79.761374, 41.999068],
                [-79.761951, 42.269861]
            ],

            [
                [-78.933161, 42.963457],
                [-78.934961, 42.965657],
                [-78.934461, 42.964257],
                [-78.933161, 42.963457]
            ],
            [
                [-78.92426, 42.952357],
                [-78.92036, 42.954557],
                [-78.92886, 42.956457],
                [-78.92816, 42.955457],
                [-78.92426, 42.952357]
            ],
            [

                [-78.902609, 42.911768],
                [-78.901122, 42.929442],
                [-78.906739, 42.933805],
                [-78.906259, 42.929557],
                [-78.902609, 42.911768]
            ],
            [

                [-79.064667, 43.078556],
                [-79.071667, 43.078856],
                [-79.073267, 43.080156],
                [-79.071267, 43.083356],
                [-79.064667, 43.078556]

            ],
            [

                [-78.946165, 42.956954],
                [-79.015493, 42.990871],
                [-78.999465, 43.064756],
                [-78.89966, 43.041057],
                [-78.943945, 42.995081],
                [-78.946165, 42.956954]

            ],
            [

                [-78.88566, 43.023557],
                [-78.88836, 43.031957],
                [-78.88826, 43.034457],
                [-78.882868, 43.030771],
                [-78.88566, 43.023557]

            ],
            [

                [-78.956761, 42.958757],
                [-78.961462, 42.959357],
                [-78.963462, 42.961057],
                [-78.958362, 42.961457],
                [-78.956761, 42.958757]

            ]
        ]

    }
  }
]}

任何人都知道如何正确有效地做到这一点我已经坚持了大约 2 天没有成功

4

5 回答 5

7

有一个工具可以将（标准）KML 转换为 geoJSON（见下面的链接）。不过，它是用 nodejs 编写的。

https://github.com/tmcw/togeojson#readme

于 2013-04-20T08:29:56.393 回答
3

KMZ 为 KML

KMZ 本质上是一个 ZIP 存档。只需使用任何 zip 工具解压缩包含的 KML。Windows 用户可能需要将文件扩展名更改为.zip.

KML 转 GeoJSON

使用 Python 实用程序kml2geojson：

$ pip install kml2geojson --user
$ k2g input.kml output_directory

什么不工作

  • ogr2ogr：无法处理 KML 中的多层
于 2019-02-14T13:19:49.910 回答
1

为了回应最近的回答——迭代每个 KML 层是一种很好的解决方法，在用 Python 和 R 清理数据时出现了很多，我想它可以适用于任何语言。

例如，在 R 和使用 GDAL 中，它看起来像：

library(rgdal)
library(sf)
library(plyr)
library(dplyr)

data <- "INPUT KML"
kml_Layers <- ogrListLayers(data)
iterate <- length(kml_Layers) 

iterate_layers <- function(i){
      layer_i <- st_read(data, kml_Layers[i])
      return(layer_i)
    }

loops <- 1:iterate
Result_data <- lapply(iterate_layers, loops)
results <- ldply(Result_data)

writeOGR(results, "Data_geojson", layer="Data_geojson", driver="GeoJSON")

我知道这不是 PHP，但是一旦我开始以这种方式接近 KML，它就开始为我节省大量时间。

于 2019-02-17T04:30:23.740 回答
0

KMZ 到 GeoJson

            kmz = ZipFile("demo.kmz", 'r')
            kmz.extractall()
            os.rename('doc.kml','demo.kml')
            kml2geojson.main.convert('demo.kml', '')

KML 到 GeoJson

kml2geojson.main.convert('demo.kml', '')
于 2021-04-20T05:34:18.073 回答
0

这可能会在 node.js 中停止

const tj = require('@mapbox/togeojson');
const JSZip = require('jszip');
const parser = new DOMParser();

          fetch(url)
          .then( response => response.blob() )
          .then( blob =>{
              var reader = new FileReader() ;
              reader.onload = function(){ 
                console.log(this.result) ;
                var zip = new JSZip();
                JSZip.loadAsync(this.result.split(',')[1], {base64: true}).then(zip=>{
                  console.log(zip.files);
                  zip.file("doc.kml").async("text").then(function (text) {
                    var kml = parser.parseFromString(text, "application/xml");
                    var converted = tj.kml(kml);
                   
                 

                });
              } ;
              reader.readAsDataURL(blob) ;
          }) ;
于 2021-09-18T02:39:40.823 回答