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我想检索 KpiName 键(KpiData 是 kpiName 中的数组是字典键)和下面提到的我的数据结构

--Array of dictionaries inside array of dictinary
ex..listOfProjectsArray--(
        {
        alertSeverity = 1;
        customerName = TPMG;
        endDate = "05-05-2013";
        isProjectHide = 1;
        kpiData =         (
                        {
                KpiName = "Change Request ";
                kpiActual = 14;
                kpiPlanned = "";
                kpiUnit = "";
            },
                        {
                KpiName = "Aged Debit";
                kpiActual = 24000;
                kpiPlanned = "";
                kpiUnit = EUR;
            },
        );
        lastInvoiceDate = "05-04-2013";
        nextBillingDate = "05-04-2013";
        nextMilestoneDate = "10-04-2013";
        nextReviewDate = "08-04-2013";
        plannedCompletionDate = "04-05-2013";
        projectID = 3000;
        projectName = "Rain Harvesting";
        projectSortType = "";
        projectStatus = 1;
        startDate = "01-01-2013";
    },

我试过这个,但它返回 null

   NSString *kpiName = [[[[listOfProjectsArray objectAtIndex:indexPath.row] valueForKey:@"kpiData"] objectAtIndex:0]valueForKey:@"kpiName"];
       NSLog(@"kpiname:%@", kpiName);
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2 回答 2

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我被提到错误的字典键

NSString *kpiName = [[[[listOfProjectsArray objectAtIndex:indexPath.row] valueForKey:@"kpiData"] objectAtIndex:0]valueForKey:@"kpiName"];
       NSLog(@"kpiname:%@", kpiName);

正确的是KpiNamekey 而不是kpiName.

于 2013-04-17T07:25:34.530 回答
0

尝试这个

    NSString *kpiName =[[[[listOfProjectsArray objectAtIndex:indexPath.row] objectForKey:@"kpiData"]objectAtIndex:0]objectForKey:@"KpiName"];
于 2013-04-16T12:01:55.433 回答