-1

我试图了解使用“选择器”在多维数组中查找元素的方式。

$vars = array(
    'site' => 'Stackoverflow',
    'menu' => array(
        'items' => array('Questions', 'Tags', 'Users', 'Badges', 'Unanswered'),
    ),
    'sidebar' => array(
        'tags' => array(
            'c_sharp' => 68,
            'java' => 62,
            'javascript' => 52,
            'jquery' => 50
        )
    )
);

我想要一些功能mixed find(string $selector, array $array)。

用法

$site = find('site', $vars);
// result: "Stackoverflow"

$menuItems = find('menu.items', $vars);
// result: ["Questions", "Tags", "Users", "Badges", "Unanswered"]

$tags = find('sidebar.tags', $vars);
// result: ["c_sharp" => 68, "java" => 62, "javascript" => 52, "jquery" => 50]

$javascriptQuestionsCount = find('sidebar.tags.javascript', $vars);
// result: 52

$undefinedElement = find('footer.copyright.year', $vars);
// result: null

谁能建议我一种实现这种功能的方法，或者有一些现成的解决方案？

提前致谢。

4

2 回答 2

3

Laravel 有一个函数可以做到这一点，它被称为array_get()

您可能想忽略该value()功能，但您可以return $default;改为。

/**
 * Get an item from an array using "dot" notation.
 *
 * <code>
 *      // Get the $array['user']['name'] value from the array
 *      $name = array_get($array, 'user.name');
 *
 *      // Return a default from if the specified item doesn't exist
 *      $name = array_get($array, 'user.name', 'Taylor');
 * </code>
 *
 * @param  array   $array
 * @param  string  $key
 * @param  mixed   $default
 * @return mixed
 */
function array_get($array, $key, $default = null)
{
    if (is_null($key)) return $array;

    // To retrieve the array item using dot syntax, we'll iterate through
    // each segment in the key and look for that value. If it exists, we
    // will return it, otherwise we will set the depth of the array and
    // look for the next segment.
    foreach (explode('.', $key) as $segment)
    {
        if ( ! is_array($array) or ! array_key_exists($segment, $array))
        {
            return value($default);
        }

        $array = $array[$segment];
    }

    return $array;
}

/**
 * Return the value of the given item.
 *
 * If the given item is a Closure the result of the Closure will be returned.
 *
 * @param  mixed  $value
 * @return mixed
 */
function value($value)
{
    return (is_callable($value) and ! is_string($value)) ? call_user_func($value) : $value;
}
于 2013-04-16T11:17:04.327 回答
0

像这样的东西：

   <?php
$vars = array(
    'site' => 'Stackoverflow',
    'menu' => array(
        'items' => array('Questions', 'Tags', 'Users', 'Badges', 'Unanswered'),
    ),
    'sidebar' => array(
        'tags' => array(
            'c_sharp' => 68,
            'java' => 62,
            'javascript' => 52,
            'jquery' => 50
        )
    )
);

function find ($key, $array){
  $keys = explode(".",$key);
    $currArr = $array;
    for ($i=0; $i<count($keys);$i++){
        if (isset($currArr[$keys[$i]])){
          $currArr = $currArr[$keys[$i]];
        }else{
          return null;
        }
    }

    return $currArr;
}

$site = find('site', $vars);
print_r($site);
echo "<br />";

$menuItems = find('menu.items', $vars);
print_r($menuItems);
echo "<br />";

$tags = find('sidebar.tags', $vars);
print_r($tags);
echo "<br />";

$javascriptQuestionsCount = find('sidebar.tags.javascript', $vars);
print_r($javascriptQuestionsCount);
echo "<br />";

$undefinedElement = find('footer.copyright.year', $vars);
print_r($undefinedElement);
echo "<br />";
?>

输出：

Stackoverflow
Array ( [0] => Questions [1] => Tags [2] => Users [3] => Badges [4] => Unanswered ) 
Array ( [c_sharp] => 68 [java] => 62 [javascript] => 52 [jquery] => 50 ) 
52
null

小提琴：

http://phpfiddle.org/lite/code/u7u-8jx

无需任何库即可工作，只需简单的 PHP。

于 2013-04-16T11:23:55.323 回答