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我正在尝试创建具有几条垂直线的python程序，这些垂直线充当随机生成的点或“点”（如代码中所指）以随机程度绘制直线的边界。如果直线与垂直“边界”之一相交，我想让它改变颜色。我有一张我正在努力实现的目标的图片，这可能会更清楚地解释我的情况。我在下面发布的代码绘制了“垂直边界”并在该区域内随机生成了点，但这就是我卡住的地方。

我的目标是：

程序示例

我目前的代码：

setup(750,750)
screen_size = 750
max_coord = (screen_size - 30) / 2
### change the number of dots you have via that variable
num_dots = 500
bgcolor('yellow')
dot_size=5


reset() # Create an empty window 
pi = Turtle()
hideturtle()

def parallel_lines(number):
    pi.pensize(2)
    pi.pencolor('black')
    width = pi.window_width()
    height = pi.window_height()
    pi.setheading(90)
    pi.penup()
    pi.setposition(width/-2, height/-2)
for i in range(1, number +2):
    pi.pendown()
    pi.forward(height)
    pi.penup()
    pi.setposition(width/-2+i*(width/(number+1)),height/-2)
parallel_lines(7)

## centre turtle back in the middle of the page
goto(0,0)

### list to hold the dots
x_coords = []
y_coords = []
### Draw the dots via randomint

penup()
color("blue")
for dot_num in range(num_dots):
    dot_pos_x = randint (-max_coord, max_coord)
    dot_pos_y = randint (-max_coord, max_coord)
    goto(dot_pos_x, dot_pos_y)
    dot(dot_size)
    x_coords.append(dot_pos_x)
    y_coords.append(dot_pos_y)

done()

提前感谢任何可以提供帮助的人。

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1 回答 1

2

这是OP描述的程序的实现。如果有一条线相交，它会使用 Python 3 turtle 的撤消功能来移除这条线并以备用颜色重新绘制它：

from turtle import Turtle, Screen
from random import randint, randrange

SCREEN_SIZE = 750
PLANK_COUNT = 8
PINHEAD_SIZE = 5

FLOOR_COLOR = "yellow"
DEFAULT_COLOR = "blue"
CROSSING_COLOR = "red"

screen = Screen()
screen.setup(SCREEN_SIZE, SCREEN_SIZE)
screen.bgcolor(FLOOR_COLOR)

# configure numbers to replicate Lazzarini's setup

NUMBER_PINS = 3408
PIN_LENGTH = 78.125
PLANK_WIDTH = screen.window_width() / PLANK_COUNT

def parallel_lines(turtle, width, height):

    turtle.penup()
    turtle.setheading(90)

    turtle.sety(height / -2)

    x_coordinates = []

    for i in range(PLANK_COUNT + 1):
        x = i * PLANK_WIDTH - width / 2

        turtle.setx(x)
        turtle.pendown()
        turtle.forward(height)
        turtle.penup()
        turtle.left(180)

        x_coordinates.append(x)

    return x_coordinates


pi = Turtle(visible=False)
pi.speed("fastest")

x_coordinates = parallel_lines(pi, screen.window_width(), screen.window_height())

def crosses(x0, x1, coordinates):
    for coordinate in coordinates:
        if x0 <= coordinate <= x1 or x1 <= coordinate <= x0:
            return True
    return False

previous_crossings = crossings = 0

max_coord = screen.window_width() / 2

for pin in range(NUMBER_PINS):
    x0, y0 = randint(-max_coord, max_coord), randint(-max_coord, max_coord)

    pi.color(DEFAULT_COLOR)
    pi.goto(x0, y0)
    pi.dot(PINHEAD_SIZE)
    pi.setheading(randrange(360))
    pi.pendown()
    pi.forward(PIN_LENGTH)

    if crosses(x0, pi.xcor(), x_coordinates):
        pi.undo()
        pi.color(CROSSING_COLOR)
        pi.dot(PINHEAD_SIZE)
        pi.forward(PIN_LENGTH)

        crossings += 1

    pi.penup()

    if previous_crossings != crossings:
        estimate = (2 * PIN_LENGTH * pin) / (PLANK_WIDTH * crossings)
        print(estimate)
        previous_crossings = crossings

screen.exitonclick()

现在讲故事的其余部分。 OP 没有提到的是，这是地板上的木板图，我们在上面放针，跟踪地板上有多少交叉线，作为估计 PI 值（π ）！

阅读有关布冯的针的详细信息。要点是引脚穿过线的概率是 PI 的函数，因此我们可以将等式反过来，删除实际（或虚拟）引脚，以估计 PI。

在此处输入图像描述

该程序基于到目前为止丢弃的引脚将 PI (π) 的运行估计值输出到控制台：

...
3.121212121212121
3.1215970961887476
3.1370772946859904
3.134418324291742
3.131768953068592
3.1381381381381384
3.1384892086330933
3.1358467983243568
3.1451612903225805
3.1454979129397733
3.1458333333333335
3.1491384432560903
3.1465005931198102
3.1438721136767316
3.144208037825059
3.144542772861357
3.1419316843345113
于 2016-12-11T04:26:51.747 回答