24

如果我在 opengl-es 中准备了自定义渲染器：

public void onDrawFrame(GL10 gl)
{
    gl.glClear(GL10.GL_COLOR_BUFFER_BIT | GL10.GL_DEPTH_BUFFER_BIT);
    // here i want to draw line from [0, 0, 0] to [1, 0, 0]
}

画线最简单最快捷的方法是什么？

在普通的 OpenGL 中是：

glBegin(GL_LINES);
    glVertex3f(0, 0, 0);
    glVertex3f(1, 0, 0);
glEnd();

但是如何使用 OpenGL ES 获得相同的效果？

4

2 回答 2

41

我是 OpenGL ES 2.0 的新手，但我创建了一个线类。

public class Line {
    private FloatBuffer VertexBuffer;

    private final String VertexShaderCode =
        // This matrix member variable provides a hook to manipulate
        // the coordinates of the objects that use this vertex shader
        "uniform mat4 uMVPMatrix;" +

        "attribute vec4 vPosition;" +
        "void main() {" +
        // the matrix must be included as a modifier of gl_Position
        "  gl_Position = uMVPMatrix * vPosition;" +
        "}";

    private final String FragmentShaderCode =
        "precision mediump float;" +
        "uniform vec4 vColor;" +
        "void main() {" +
        "  gl_FragColor = vColor;" +
        "}";

    protected int GlProgram;
    protected int PositionHandle;
    protected int ColorHandle;
    protected int MVPMatrixHandle;

    // number of coordinates per vertex in this array
    static final int COORDS_PER_VERTEX = 3;
    static float LineCoords[] = {
        0.0f, 0.0f, 0.0f,
        1.0f, 0.0f, 0.0f
    };

    private final int VertexCount = LineCoords.length / COORDS_PER_VERTEX;
    private final int VertexStride = COORDS_PER_VERTEX * 4; // 4 bytes per vertex

    // Set color with red, green, blue and alpha (opacity) values
    float color[] = { 0.0f, 0.0f, 0.0f, 1.0f };

    public Line() {
        // initialize vertex byte buffer for shape coordinates
        ByteBuffer bb = ByteBuffer.allocateDirect(
            // (number of coordinate values * 4 bytes per float)
            LineCoords.length * 4);
        // use the device hardware's native byte order
        bb.order(ByteOrder.nativeOrder());

        // create a floating point buffer from the ByteBuffer
        VertexBuffer = bb.asFloatBuffer();
        // add the coordinates to the FloatBuffer
        VertexBuffer.put(LineCoords);
        // set the buffer to read the first coordinate
        VertexBuffer.position(0);

        int vertexShader = ArRenderer.loadShader(GLES20.GL_VERTEX_SHADER, VertexShaderCode);
        int fragmentShader = ArRenderer.loadShader(GLES20.GL_FRAGMENT_SHADER, FragmentShaderCode);

        GlProgram = GLES20.glCreateProgram();             // create empty OpenGL ES Program
        GLES20.glAttachShader(GlProgram, vertexShader);   // add the vertex shader to program
        GLES20.glAttachShader(GlProgram, fragmentShader); // add the fragment shader to program
        GLES20.glLinkProgram(GlProgram);                  // creates OpenGL ES program executables
    }

    public void SetVerts(float v0, float v1, float v2, float v3, float v4, float v5) {
        LineCoords[0] = v0;
        LineCoords[1] = v1;
        LineCoords[2] = v2;
        LineCoords[3] = v3;
        LineCoords[4] = v4;
        LineCoords[5] = v5;

        VertexBuffer.put(LineCoords);
        // set the buffer to read the first coordinate
        VertexBuffer.position(0);
    }

    public void SetColor(float red, float green, float blue, float alpha) {
        color[0] = red;
        color[1] = green;
        color[2] = blue;
        color[3] = alpha;
    }

    public void draw(float[] mvpMatrix) {
        // Add program to OpenGL ES environment
        GLES20.glUseProgram(GlProgram);

        // get handle to vertex shader's vPosition member
        PositionHandle = GLES20.glGetAttribLocation(GlProgram, "vPosition");

        // Enable a handle to the triangle vertices
        GLES20.glEnableVertexAttribArray(PositionHandle);

        // Prepare the triangle coordinate data
        GLES20.glVertexAttribPointer(PositionHandle, COORDS_PER_VERTEX,
                                 GLES20.GL_FLOAT, false,
                                 VertexStride, VertexBuffer);

        // get handle to fragment shader's vColor member
        ColorHandle = GLES20.glGetUniformLocation(GlProgram, "vColor");

        // Set color for drawing the triangle
        GLES20.glUniform4fv(ColorHandle, 1, color, 0);

        // get handle to shape's transformation matrix
        MVPMatrixHandle = GLES20.glGetUniformLocation(GlProgram, "uMVPMatrix");
        ArRenderer.checkGlError("glGetUniformLocation");

        // Apply the projection and view transformation
        GLES20.glUniformMatrix4fv(MVPMatrixHandle, 1, false, mvpMatrix, 0);
        ArRenderer.checkGlError("glUniformMatrix4fv");

        // Draw the triangle
        GLES20.glDrawArrays(GLES20.GL_LINES, 0, VertexCount);

        // Disable vertex array
        GLES20.glDisableVertexAttribArray(PositionHandle);
    }
 }

然后在我的 Render 类中，我创建我的线条对象和一个容器，以便通过迭代项目并在 onDrawFrame 中调用 Line.draw 方法来绘制。

以下是我创建的一些线来制作地平线：

    Line eastHorz = new Line();
    eastHorz.SetVerts(10f, 10f, 0f, 10f, -10f, 0f);
    eastHorz.SetColor(.8f, .8f, 0f, 1.0f);
    Line northHorz = new Line();
    northHorz.SetVerts(-10f, 10f, 0f, 10f, 10f, 0f);
    northHorz.SetColor(0.8f, 0.8f, 0f, 1.0f);
    Line westHorz = new Line();
    westHorz.SetVerts(-10f, -10f, 0f, -10f, 10f, 0f);
    westHorz.SetColor(0.8f, 0.8f, 0f, 1.0f);
    Line southHorz = new Line();
    southHorz.SetVerts(-10f, -10f, 0f, 10f, -10f, 0f);
    southHorz.SetColor(0.8f, 0.8f, 0f, 1.0f);
    Lines.add(eastHorz);
    Lines.add(northHorz);
    Lines.add(westHorz);
    Lines.add(southHorz);
于 2013-04-25T19:46:42.893 回答
8

感谢Rodney Lambert您提供的Line课程。但是，在onDrawFrame中提供一个更简单的调用也会很好，例如：

Line vertLine = new Line();
vertLine.SetVerts(-0.5f, 0.5f, 0f, -0.5f, -0.5f, 0f);
vertLine.SetColor(.8f, .8f, 0f, 1.0f);
vertLine.draw(mMVPMatrix);

vertLine.SetVerts(-0.5f, 0.5f, 0f, -0.5f, -0.5f, 0f);

绝对在视口内创建一条可见的线

于 2013-06-25T07:30:46.563 回答