ruby - Ruby：如何链接方法数组（或拆分字符串）中指定的方法？

Question

当方法调用被指定为数组时，如何在 Ruby 中链接方法？

例子：

class String
  def bipp();  self.to_s + "-bippity"; end
  def bopp();  self.to_s + "-boppity"; end
  def drop();  self.to_s + "-dropity"; end
end

## this produces the desired output
##
puts 'hello'.bipp.bopp.drop #=> hello-bippity-boppity-dropity

## how do we produce the same desired output here?
##
methods   =   "bipp|bopp|drop".split("|")
puts 'world'.send( __what_goes_here??__ ) #=> world-bippity-boppity-droppity

[Ruby 纯粹主义者注意：本示例采用了风格自由。有关分号、括号、注释和符号的首选用法说明，请随时查阅 Ruby 样式指南（例如，https://github.com/styleguide/ruby）]

Answer 1

Try this:

methods   =   "bipp|bopp|drop".split("|")
result = 'world'
methods.each {|meth| result = result.send(meth) }
puts result

or, using inject:

methods = "bipp|bopp|drop".split("|")
result = methods.inject('world') do |result, method|
  result.send method
end

or, more briefly:

methods = "bipp|bopp|drop".split("|")
result = methods.inject('world', &:send)

By the way - Ruby doesn't need semicolons ; at the end of each line!

Answer 2

methods   =   "bipp|bopp|drop".split("|")
result = 'world'
methods.each {|meth| result = result.method(meth).call }
puts result #=> world-bippity-boppity-dropity

或者

methods = "bipp|bopp|drop".split("|")
methods.each_with_object('world') {|meth,result| result.replace(result.method(meth).call)} #=> world-bippity-boppity-dropity