作为实验室的一部分，我需要设计一种方法来计算当前月份的日期和年份。我将使用 gettimeofday() 函数，它给出了自 1970 年 1 月 1 日以来的秒数。
我知道有些函数可以为我进行转换，但是设计要求是我创建自己的算法来将秒数转换为月日和年。我想要实现我的设计的方式是为十二个月中的每个月和相应的天数提供一个查找表。现在的逻辑让我有点困惑。
棘手的部分是处理闰年。我知道 1972 年是自 1970 年以来的第一个闰年。自该日期起每 4 年发生一次闰年。在这个作业中给我的提示是，天之后的下一个最大周期是 4 年。因此，如果我将自 1970 年以来的天数乘以 1461（4 年的天数），我知道我可以得到剩余的天数。在这一点上，我的逻辑迷路了。如果我将它除以 1461，它只会告诉我已经过去了多少个 4 年。
我想实现的表看起来像这样（我知道编码不完全正确，只是为了显示我得到了什么）：
struct Monthdays
{
int days;
char* Monthname[]
};
Monthdays lookupMonths[]
{
{31,"January"}
{28,"February"}
.
.
.
};
我试图弄清楚如何使用天数或一些东西来创建正确的索引来遍历这个“表”............我希望在这里问这个没问题。我一直在与逻辑或几天作斗争......
这是我现在遇到的这个问题的代码，效率很低。
ExpandedTime* localTime(
struct timeval* tv, // Pointer to timeval struct
ExpandedTime* etime // '' '' to expandedtime strct
)
{
tzset(); // Corrects for timezone
int epochT = (tv->tv_sec) - timezone; // Epoch seconds with
int epochUT = tv->tv_usec; // epochtime microseconds
int edays; // Days since epochtime
etime->et_usec = (epochUT/milli) % milli; // Find the milliseconds
etime->et_sec = epochT % 60;
epochT /= 60; // Turn into minutes
etime->et_min = epochT % 60;
epochT /= 60; // Turn into hours
if (localtime(&tv->tv_sec)->tm_isdst !=0)
etime->et_hour = (epochT % 24) + daylight; // Hours with DST correc
else
etime->et_hour = (epochT % 24);
edays = epochT /= 24; // Turn into days
etime->et_day = epochT; // Delete up to here
etime->et_year = (epochT/365) + epochyear; // Get the current year
int trackyear; // Counter for years
int trackdays = -1; // Subtracting janurary 1st
// from days
// This will determine if it is a leapyear and adjust days accordingly
// from 1970 to current year (2013)
for (trackyear = epochyear; trackyear < etime->et_year; trackyear++)
{
if (trackyear % leapy == 0)
{
trackdays = trackdays + 366;
}
else
{
trackdays = trackdays + 365;
}
}
etime->et_day = edays - trackdays;
int trackmonth = -1; // Counter for months
// with offset to make
// january = 0
// This will give me the number of months for the buffer
do
{
switch (trackmonth)
{
// Months with 31 days
case 0:
etime->et_day = (etime->et_day) - 31;
break;
case 2:
etime->et_day = (etime->et_day) - 31;
break;
case 4:
etime->et_day = (etime->et_day) - 31;
break;
case 6:
etime->et_day = (etime->et_day) - 31;
break;
case 7:
etime->et_day = (etime->et_day) - 31;
break;
case 9:
etime->et_day = (etime->et_day) - 31;
break;
case 11:
etime->et_day = (etime->et_day) - 31;
break;
// Months with only 30 days
case 3:
etime->et_day = (etime->et_day) - 30;
break;
case 5:
etime->et_day = (etime->et_day) - 30;
break;
case 8:
etime->et_day = (etime->et_day) - 30;
break;
case 10:
etime->et_day = (etime->et_day) - 30;
break;
// Leap year month a.k.a Febuary
case 1:
if (trackyear % leapy)
{
etime->et_day = (etime->et_day) - 28;
}
else
{
etime->et_day = (etime->et_day) - 29;
}
break;
}
trackmonth++;
}
while(etime->et_day > 0);
etime->et_mon = trackmonth - 1;
// Reverts day offset from previous switch to
// accurately represent the current day
switch (etime->et_mon)
{
// Months with 31 days
case 0:
etime->et_day = (etime->et_day) + 31;
break;
case 2:
etime->et_day = (etime->et_day) + 31;
break;
case 4:
etime->et_day = (etime->et_day) + 31;
break;
case 6:
etime->et_day = (etime->et_day) + 31;
break;
case 7:
etime->et_day = (etime->et_day) + 31;
break;
case 9:
etime->et_day = (etime->et_day) + 31;
break;
case 11:
etime->et_day = (etime->et_day) + 31;
break;
// Months with only 30 days
case 3:
etime->et_day = (etime->et_day) + 30;
break;
case 5:
etime->et_day = (etime->et_day) + 30;
break;
case 8:
etime->et_day = (etime->et_day) + 30;
break;
case 10:
etime->et_day = (etime->et_day) + 30;
break;
// Leap year month a.k.a Febuary
case 1:
if (trackyear % leapy)
{
etime->et_day = (etime->et_day) + 28;
}
else
{
etime->et_day = (etime->et_day) + 29;
}
break;
}
return etime;
}