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我有以下 SQL 语句来计算基于 3 个 Wordpress 表的几个字段。我需要的是只包含 meta_key='odd' 和 meta_value >= '1.5' 的结果。我在 WHERE 语句中进行了尝试，但它不起作用，因为此查询中的大多数结果显示为 Null。

任何帮助深表感谢！

SELECT (display_name) AS 'user',
    SUM(Case When meta_key = 'status' Then meta_value = 'won' else Null End) AS 'Won',
    SUM(Case When meta_key = 'status' Then meta_value = 'lost' else Null End) AS 'Lost',
    COUNT(Case When meta_key = 'odd' Then meta_value else Null End) AS 'Total',
    ROUND (AVG(Case When meta_key = 'odd' Then meta_value else Null End), 2) AS 'Avg odd',
    ROUND (AVG(Case When meta_key = 'bet' Then meta_value else Null End), 2) AS 'Avg bet',
    ROUND (SUM(Case When meta_key = 'balance' Then meta_value else Null End), 2) AS 'Balance'
FROM wp_postmeta pm
INNER JOIN wp_posts p ON pm.post_id = p.ID 
INNER JOIN wp_users u ON p.post_author = u.ID
WHERE Month(post_date) = MONTH(CURRENT_DATE) AND p.post_status='publish' AND pm.meta_key='odd' AND pm.met.value >='1.5'
GROUP BY (display_name)
ORDER BY Balance DESC
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1 回答 1

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您需要将其移至having子句：

SELECT (display_name) AS 'user',
    SUM(Case When meta_key = 'status' Then meta_value = 'won' else Null End) AS 'Won',
    SUM(Case When meta_key = 'status' Then meta_value = 'lost' else Null End) AS 'Lost',
    COUNT(Case When meta_key = 'odd' Then meta_value else Null End) AS 'Total',
    ROUND (AVG(Case When meta_key = 'odd' Then meta_value else Null End), 2) AS 'Avg odd',
    ROUND (AVG(Case When meta_key = 'bet' Then meta_value else Null End), 2) AS 'Avg bet',
    ROUND (SUM(Case When meta_key = 'balance' Then meta_value else Null End), 2) AS 'Balance'
FROM wp_postmeta pm
INNER JOIN wp_posts p ON pm.post_id = p.ID 
INNER JOIN wp_users u ON p.post_author = u.ID
WHERE Month(post_date) = MONTH(CURRENT_DATE) AND p.post_status='publish' 
GROUP BY (display_name)
having SUM(case when pm.meta_key='odd' AND pm.meta_value >='1.5' then 1 else 0 end) > 0
ORDER BY Balance DESC

这确定每个 . 是否存在这样的行display_name。

于 2013-04-15T16:19:56.933 回答