7

我不明白这个错误:

TypeError: string is undefined function d3_time_parse(date, template, string, j) { var c, p, i = 0, n = template.length, m = string.length; ...

这是我的代码:


    var margin = {上:20,右:80,下:30,左:50},
        宽度 = 960 - margin.left - margin.right,
        高度 = 500 - margin.top - margin.bottom;

    var parseDate = d3.time.format("%Y%m%d").parse;

    var x = d3.time.scale()
        .range([0, 宽度]);

    var y = d3.scale.linear()
        .range([高度, 0]);

    var color = d3.scale.category10();

    var xAxis = d3.svg.axis()
        .scale(x)
        .orient("底部");

    var yAxis = d3.svg.axis()
        .scale(y)
        .orient("左");

    var line = d3.svg.line()
        .interpolate("基础")
        .x(函数(d) { 返回 x(d.date); })
        .y(function(d) { return y(d.index); });

    var svg = d3.select("body").append("svg")
        .attr("宽度", width + margin.left + margin.right)
        .attr("高度", 高度 + margin.top + margin.bottom)
      .append("g")
        .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

    d3.csv("data.csv", function(error, data) {
      color.domain(d3.keys(data[0]).filter(function(key) { return key !== "date"; }));

      data.forEach(函数(d){
        d.date = parseDate(d.date);
      });

      var 索引 = color.domain().map(function(name) {
        返回 {
          姓名:姓名,
          值:data.map(函数(d){
            返回{日期:d.date,索引:+d[name]};
          })
        };
      });

      x.domain(d3.extent(data, function(d) { return d.date; }));

      y.domain([
        d3.min(indexes, function(c) { return d3.min(c.values, function(v) { return v.index; }); }),
        d3.max(indexes, function(c) { return d3.max(c.values, function(v) { return v.index; }); })
      ]);

      svg.append("g")
          .attr("类", "x 轴")
          .attr("变换", "翻译(0," + 高度 + ")")
          .call(xAxis);

      svg.append("g")
          .attr("类", "y 轴")
          .call(yAxis)
        .append("文本")
          .attr("变换", "旋转(-90)")
          .attr("y", 6)
          .attr("dy", ".71em")
          .style("文本锚", "结束")
          .text("变化 (%)");

      var index = svg.selectAll(".index")
          .data(索引)
        .enter().append("g")
          .attr("类", "索引");

      index.append("路径")
          .attr("类", "行")
          .attr("d", function(d) { return line(d.values); })
          .style("stroke", function(d) { return color(d.name); });

      index.append("文本")
          .datum(function(d) { return {name: d.name, value: d.values[d.values.length - 1]}; })
          .attr("transform", function(d) { return "translate(" + x(d.value.date) + "," + y(d.value.index) + ")"; })
          .attr("x", 3)
          .attr("dy", ".35em")
          .text(function(d) { return d.name; });
    });

我的 csv 文件如下所示:

日期,DAX,CAC40,FTSE,NASDAQ,其他
20060407,-0.000712859,-0.009013212,0.010819606,0.009846526,0.003082604
20060413,-0.007765968,-0.024263398,0.011238971,0.004128621,0.005952774
20060421,0.02261859,0.00330204,0.028734861,0.001688981,0.003459211
20060428,0.007170521,-0.007531405,0.010534438,-0.002416181,0.004012361
...

有人可以帮我吗?谢谢你

4

1 回答 1

8

日期,DAX,CAC40,FTSE,NASDAQ,其他

JavaScript 变量名区分大小写,因此在解析带有上述标题的 CSV 文件时,您需要引用以下字段:

d.Date // note the uppercase D
d.DAX // note all uppercase

这是来自 d3 wiki https://github.com/mbostock/d3/wiki/CSV#wiki-parse的示例

年份、品牌、型号、长度

1997,福特,E350,2.34

2000,水星,美洲狮,2.38

当使用 d3 的 CSV 解析器解析时,结果数据将由以下数组表示:

[
  {"Year": "1997", "Make": "Ford", "Model": "E350", "Length": "2.34"},
  {"Year": "2000", "Make": "Mercury", "Model": "Cougar", "Length": "2.38"}
]

注意大写的对象键。要访问第一个条目的年份,需要一个带有大写 Y 的“年份” data[0].Year

因此,在您的forEach功能中,您将需要:

data.forEach(function (d) {
    d.Date = parseDate(d.Date);
});

...后来:

return {date: d.Date, index: +d[name]};
于 2013-04-15T13:49:57.567 回答