2

你能帮我在数组中搜索十进制数或它的一部分". "（点和后面的空格），然后用零替换它或删除点吗？

下面是数组的一部分：

Array ( [2] => AUD,ADF,1,06-01-2001,3.,3.9532
        [3] => AUD,ADP,1,06-02-2001,99.8222,99.6682
        [4] => AUD,AED,1,06-01-2001,1.8687,1.8664
        [5] => AUD,AFA,1,06-01-2001,2416.57,2413.95
        [6] => AUD,AFN,1,06-01-2001,2416.57,2413.95
        [7] => AUD,ALL,1,06-01-2001,77.,75.9759
        [8] => AUD,AMD,1,06-03-2001,NULL,NULL
        [9] => AUD,ANG,1,06-01-2001,0.9056,0.9046
        [10] => AUD,AOA,1,06-01-2001,3.0751,2.9961
        [11] =>

请看[7]有没有类似的数字77。或在[2]那里3。（点后没有任何内容）。

4

4 回答 4

4

使用preg_replace()：

$array = array(
    'AUD,ADF,1,06-01-2001,3.,3.9532',
    'AUD,ADP,1,06-02-2001,99.8222,99.6682',
    'AUD,ALL,1,06-01-2001,77.,75.9759',
    'AUD,ALL,1,06-01-2001,78.   ,75.9759'
);
//                         ----RegEx Pattern---  Replace   Input
//                         \/       \/       \/    \/       \/
$new_array = preg_replace('/(\d+)\.(\s*)(?!\d)/', '$1', $array);
//                           ^^^ ^^ ^^^^ ^^^^
//                            |   |   |    | 
// Match any digits [0-9] <---|   |   |    |
//         Match a point  <-------|   |    |
// Match spaces and make it optional<--    |
//                                         |
// Lookahead, which means that if there <--|
// is no digits after:                  <--|
// digit[point][0 or several spaces]    <--|
// The whole thing won't be matched.    <--|

// Addition: the first (\d+) is the first match group
// That's why we used $1 in replace !

// \d -> [0-9]
// \s -> space
// \. -> points have to be escaped
// (?!) -> Lookbehind (check : http://php.net/manual/en/regexp.reference.assertions.php)
// * -> Occurs 0 time or plus
// + -> occurs 1 time or plus
// The '/' at the begin and the end are delimiters

print_r($new_array);

输出：

Array
(
    [0] => AUD,ADF,1,06-01-2001,3,3.9532
    [1] => AUD,ADP,1,06-02-2001,99.8222,99.6682
    [2] => AUD,ALL,1,06-01-2001,77,75.9759
    [3] => AUD,ALL,1,06-01-2001,78,75.9759
)

编辑：回答下面评论中的问题：

正则表达式是关于正则模式的。从所需的输出中，我可以看到您希望将除数字（整数和双精度/浮点数）之外的所有内容都放在引号中，我们还可以将日期放在引号之间。所以这是一种方法：

$new_array = preg_replace('/(\d+)\.(\s*)(?!\d)/', '$1', $array); // remove some dots & spaces
$new_array_2 = preg_replace('/([a-zA-Z]+|\d+-\d+-\d+)/', '\'$1\'', $new_array);
//            Match letters <--^-^-^-^-^  ^-^-^-^-^---> Match digits-digits-digits (for the date part), I don't want to use a LOOOONG RegEx to check if it's valid ...

print_r($new_array); // First replacement
print_r($new_array_2); // Second replacement

通过使用一些 PHP-Fu，还有另一种更可靠的方法：

$new_array = preg_replace('/(\d+)\.(\s*)(?!\d)/', '$1', $array); // remove some dots & spaces
// For this code YOU NEED PHP 5.3+ since it's using anonymous functions
$new_array_2 = array_map(function($val){
    $pieces = explode(',', $val);
    $pieces2 = array_map(function($val2){
        if(preg_match('/^\d+(\.\d+)?$/', $val2)){
            return $val2;
        }else{
            return "'$val2'";
        }
    }, $pieces);
    return(implode(',',$pieces2));
}, $new_array);

print_r($new_array);
print_r($new_array_2);

输出：

Array
(
    [0] => AUD,ADF,1,06-01-2001,3,3.9532
    [1] => AUD,ADP,1,06-02-2001,99.8222,99.6682
    [2] => AUD,ALL,1,06-01-2001,77,75.9759
    [3] => AUD,ALL,1,06-01-2001,78,75.9759
)
Array
(
    [0] => 'AUD','ADF',1,'06-01-2001',3,3.9532
    [1] => 'AUD','ADP',1,'06-02-2001',99.8222,99.6682
    [2] => 'AUD','ALL',1,'06-01-2001',77,75.9759
    [3] => 'AUD','ALL',1,'06-01-2001',78,75.9759
)
于 2013-04-15T07:16:37.393 回答
1

您可以使用 intval() 将浮点数转换为整数：http ://php.net/manual/en/function.intval.php 看起来您可能必须拆分值（用逗号分隔），转换它们然后再次加入他们...

于 2013-04-15T07:13:00.223 回答
1

使用str_replace，您可以将完整数组作为输入传递：

$j = array('AUD,ADF,1,06-01-2001,3.,3.9532','AUD,ADP,1,06-02-2001,99.8222,99.6682','AUD,AED,1,06 -01-2001,1.8687,1.8664','AUD,AFA,1,06-01-2001,2416.57,2413.95','AUD,AFN,1,06-01-2001,2416.57,2413.95','AUD,ALL ,1,06-01-2001,77.,75.9759','AUD,AMD,1,06-03-2001,NULL,NULL','AUD,ANG,1,06-01-2001,0.9056,0.9046' ,'AUD,AOA,1,06-01-2001,3.0751,2.9961');

$j = str_replace(".,", "," , $j);

打印_r($j);

输出

Array
 (
[0] => AUD,ADF,1,06-01-2001,3,3.9532
[1] => AUD,ADP,1,06-02-2001,99.8222,99.6682
[2] => AUD,AED,1,06-01-2001,1.8687,1.8664
[3] => AUD,AFA,1,06-01-2001,2416.57,2413.95
[4] => AUD,AFN,1,06-01-2001,2416.57,2413.95
[5] => AUD,ALL,1,06-01-2001,77,75.9759
[6] => AUD,AMD,1,06-03-2001,NULL,NULL
[7] => AUD,ANG,1,06-01-2001,0.9056,0.9046
[8] => AUD,AOA,1,06-01-2001,3.0751,2.9961
)
于 2013-04-15T07:22:56.457 回答
0

你必须使用 array_walk() 和 preg_replace() 来做到这一点。正则表达式的表达式应该类似于 (.)[,\s]

于 2013-04-15T07:21:08.150 回答