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假设我有这种解析器类型:

newtype Parser a = Parser { runParser :: String -> Maybe (a, String) }

这个原子解析器单元:

satisfy :: ( Char -> Bool ) -> Parser Char
satisfy g = Parser $ \stream -> case stream of
    (x:xs) | g x -> Just ( x, xs )
    otherwise    -> Nothing

解析器实现了这三个接口:

instance Functor Parser where
    fmap g ( Parser p ) = Parser $ \xs0 -> p xs0 >>= \(x,xs) -> return ( g x, xs )


instance Applicative Parser where
    pure a                      = Parser $ \xs0 -> Just ( a, xs0 )
    (Parser p1) <*> (Parser p2) = Parser $ \xs0 -> do
        (x1, xs1) <- p1 xs0
        (x2, xs2) <- p2 xs1
        return ( x1 x2, xs2 )

instance Alternative Parser where
    empty                        = Parser $ const Nothing
    (Parser p1) <|> (Parser p2)  = Parser $ \ss -> let ss1 = p1 ss in case ss1 of
        Nothing  -> p2 ss
        _        -> ss1

satisfy现在据我了解,我现在可以通过使用应用程序接口进行链接来弹出更高级别的抽象并构建更复杂的解析器。例如:

-- | A parser that parses the first two chars in the stream if they are upper case
uParser = satisfy isUpper
parser1 = ( (:) <$> uParser ) <*> ( (\x -> [x]) <$> uParser )
runParser parser1 "HEllo" = Just ("HE","llo")
runParser parser1 "Hello" = Nothing

太好了,现在如果我想构造一个计算,以便解析器解析流中的所有大写字母,直到遇到小写字母,该怎么办?用例:

runParser idealParser "hello"             = Nothing
runParser idealParser "HEllo"             = Just ("HE","llo")
runParser idealParser "HELLOIAMnotincaps" = Just ("HELLOIAM", "notincaps")

我如何表达这种不确定长度的概念?

4

1 回答 1

7

由于您有一个Alternative实例,您可以简单地使用Control.Applicative.some来匹配一个或多个事件的列表。

> runParser (some uParser) "hello"
Nothing
> runParser (some uParser) "HEllo"
Just ("HE","llo")
> runParser (some uParser) "HELLOIAMnotincaps"
Just ("HELLOIAM","notincaps")

要手动实现它,您可以使用两个相互递归的解析器,例如

zeroOrMore = oneOrMore <|> pure []
oneOrMore  = (:) <$> uParser <*> zeroOrMore
于 2013-04-15T01:29:30.697 回答