4

我有一个我设置值的 POJO，pojo 是：

public class CreateRequisitionRO extends AbstractPortfolioSpecificRO {

    private static final long serialVersionUID = 2418929142185068821L;

    private BigDecimal transSrlNo;
    private String transCode;
    private InflowOutflow inflowOutflow;

public BigDecimal getTransSrlNo() {
        return transSrlNo;
    }

    public void setTransSrlNo(BigDecimal transSrlNo) {
        this.transSrlNo = transSrlNo;
    }

    public InflowOutflow getInflowOutflow() {
        return inflowOutflow;
    }

    public void setInflowOutflow(InflowOutflow inflowOutflow) {
        this.inflowOutflow = inflowOutflow;
    }
    public String getTransCode() {
        return transCode;
    }
}

这就是我设置值的方式：

CreateRequisitionRO[] request = new CreateRequisitionRO[1];
    request[0].setTransSrlNo(new BigDecimal(1));
    request[0].setTransCode("BUY");
    request[0].setInflowOutflow(InflowOutflow.I);

now i would like to convert/serialize the above java pojo to Json string.

有人能帮我怎么做吗？

此致

4

2 回答 2

7

如另一个答案中所述， XStream或GS​​ON将对您进行排序。按照XStream 上的 JSON 教程进行操作，您的代码将如下所示：

        CreateRequisitionRO product = new CreateRequisitionRO();
        XStream xstream = new XStream(new JettisonMappedXmlDriver());
        xstream.setMode(XStream.NO_REFERENCES);
        xstream.alias("product", Product.class);

        System.out.println(xstream.toXML(product));

使用 GSON，您的代码将如下所示：

CreateRequisitionRO obj = new CreateRequisitionRO();
Gson gson = new Gson();
String json = gson.toJson(obj);

选择你的图书馆，然后去。

于 2013-04-15T07:28:18.203 回答
1

您可以使用 Gson 库为您提供帮助

于 2013-04-15T07:17:45.257 回答