我正在创建一个 WinJS 应用程序并使用 XMLHttpRequest 将照片作为 blob 发送到 Flask 网络服务器。
openPicker.pickSingleFileAsync().then(function (file) {
file.openAsync(Windows.Storage.FileAccessMode.read).done(function (stream) {
var blob = MSApp.createBlobFromRandomAccessStream("application/octet-stream", stream);
var fdata = new FormData();
fdata.append("file", blob, "photo.jpg");
var xmlhttp = new XMLHttpRequest();
xmlhttp.open("POST", "http://127.0.0.1:5000/api/addPhoto", true);
xmlhttp.setRequestHeader("Content-type", "multipart/form-data");
xmlhttp.send(fdata);
});
});
这会产生以下 HTTP 请求:
POST http://127.0.0.1:5000/api/addPhoto HTTP/1.1
Accept: */*
Content-Type: application/octet-stream, multipart/form-data; boundary=---------------------------7dd2a320aa0ec0
Accept-Language: en-US,en;q=0.7,ja;q=0.3
UA-CPU: AMD64
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.2; Trident/6.0; MSAppHost/1.0)
Host: 127.0.0.1:5000
Content-Length: 9471100
Connection: Keep-Alive
Pragma: no-cache
-----------------------------7dd2a320aa0ec0
Content-Disposition: form-data; name="file"; filename="photo.jpg"
Content-Type: application/octet-stream
处理 Flask Web 服务器上的请求
UPLOAD_FOLDER = '/images'
@app.route('/api/addPhoto', methods=['POST'])
def addPhoto():
if request.method == 'POST':
f = request.files['file']
if f and allowed_file(f.filename):
return "error" #add error response here
else:
filename = secure_filename(f.filename)
f.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
f.close
return "ok" #add success response here
我收到以下错误:
TypeError: 'ImmutableMultiDict' object is not callable
我有几个问题找不到答案:
- 我是否以正确的格式发送数据?我是否正确地将数据附加到我的表单中?
- 我的 HTTP 内容类型是否正确?
- 我是否试图错误地从 HTTP 请求中提取文件?
谢谢!