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这是我到目前为止的代码。该程序应该询问用户一个单词并确定其中元音/辅音的数量。用户完成后，程序应该给他们元音/辅音的平均数量。一些开始的代码是不同的（在Vand之间不同C），因为我试图找出哪个可以工作

#Okay, this is the updated version of the code where I combined @AshwiniChaudhary 's code and mine

现在我得到一个 IndexError: tuple index out of range

我试着在这里和其他几个网站上查找它，但并没有真正找到答案，我不想在这里问同样的问题两次

print("Hello!")
import sys
import re


def VOCO():
VOCO = input("Search for VOWELS or CONSONANTS: ")

if VOCO == "VOWELS":
    VOW = input("Please input word for VOWEL counting: ")
    re.findall(r'[aeiouAEIOU]', VOW)
    V = int(len(re.findall(r'[aeiouAEIOU]', VOW)))
    print(V)


elif VOCO == "CONSONANTS":
    CON = input("Please input word for CONSONANT counting: ")
    re.findall(r'[bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ]', CON)
    C = int(len(re.findall(r'[bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ]', CON)))
    print(C)

else:
    print("Please use either VOWELS or CONSONANTS in selection.")
from string import ascii_lowercase as al
def find_vo_cons2(strs,val):
    vowels="aeiou"
    consonants=set(al)-set(vowels) #set containing only consonants   
    le=float(len(strs))

    vowel_count=0
    consonant_count=0

    for x in strs:
        if x.lower() in vowels:
            vowel_count+=1
        elif x.lower() in consonants:
            consonant_count+=1
    if val in ("V","v"):
        return vowel_count/le
    elif val in ("C","c"):
        return consonant_count/le


def CNT(): True or False
CNT = input("Would you like to continue (YES/NO)? ")

if CNT() : "YES"
condition(True)
VOCO()

else:
        strs = (VOW or CON)
        print("The average of {0} count is {1}".format(find_vo_cons2(strs,VOCO)))
        sys.exit
VOCO()
while True:
    VOCO()
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1 回答 1

0

我认为您也可以在不使用regex的情况下执行此操作：

from string import ascii_lowercase as al
def find_vo_cons(strs,val):
    vowels="aeiou"
    consonants=set(al)-set(vowels) #set containing only consonants   
    le=float(len(strs))

    vowel_count=0
    consonant_count=0

    for x in strs:
        if x.lower() in vowels:
            vowel_count+=1
        elif x.lower() in consonants:
            consonant_count+=1

    if val in ("V","v"):
        return vowel_count/le
    elif val in ("C","c"):
        return consonant_count/le

def main():
    VOCO = input("Search for VOWELS(v) or CONSONANTS(c): ")
    dic={"v":"Vowels","c":"Consonants"}
    strs=  input("Enter the string: ")
    print ("The average of {0} count is {1}".format(dic[VOCO.lower()],find_vo_cons(strs,VOCO)))

main()

输出：

~$ python3 so.py
Search for VOWELS(v) or CONSONANTS(c): v
Enter the string: foObAr
The average of Vowels count is 0.5

~$ python3 so.py
Search for VOWELS(v) or CONSONANTS(c): c
Enter the string: qwertyuiop
The average of Consonants count is 0.6
于 2013-04-14T19:18:59.177 回答