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是否可以使用通用异常处理程序捕获 Python 应用程序的所有线程的异常？

考虑以下示例。我想CTRL+C从主线程中捕获，但有时它会被一个不会终止其他线程的工作线程捕获。这是这种情况下的输出：

^CTraceback (most recent call last):
  File "thread-example.py", line 50, in <module>
    main()
  File "thread-example.py", line 30, in main
    t.join(1)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 675, in join
    self.__block.wait(delay)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/threading.py", line 263, in wait
    _sleep(delay)
KeyboardInterrupt

这是测试应用程序。

#!/usr/bin/python

import os
import sys
import threading
import time
import subprocess
import signal


class Worker(threading.Thread):
    def __init__(self, name):
        threading.Thread.__init__(self)
        self.kill_received = False
        self.daemon = True
        self.name = name

    def run(self):
        while not self.kill_received:
            time.sleep(1)
            print self.name

def main():
    threads = []

    for i in xrange(10):
        t = Worker('worker-%d' % i)
        threads.append(t)
        t.start()
        t.join(1)

    while len(threads) > 0:
        try:
            threads = [t for t in threads if t is not None and t.isAlive()]
            time.sleep(1)
        except KeyboardInterrupt:
            print "Ctrl-c received! Sending kill to threads..."
            for t in threads:
                t.kill_received = True
            # wait for threads to finish gracefully, then kill them anyway.
            # since all threads are daemons, they should finish once the main 
            # loop terminates
            for i in xrange(5):
                print '%i ...' % (5-i)
                time.sleep(1)
            print 'Exit!'
            os._exit(1)

if __name__ == '__main__':
    main()
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1 回答 1

1

Ctrl-C 本身并不是一个例外，而是一个信号。您可以做的是将除“主”线程之外​​的所有生成线程设置为忽略它，如下所示：

import signal
signal.signal(signal.SIGINT, signal.SIG_IGN)
于 2013-04-14T11:29:36.087 回答