jquery - How to set a variable with the Jquery all(*) selector

Question

I have this code which will hide everything inside a certain div:

$('#middlecolumn *').hide();

So now I would like to set the ID as a variable, so I did:

var qw = '#middlecolumn';

$(qw + '*').hide();

This doesn't seem to work. It hides the ID as well as everything inside it. How do I write it the proper way?

score 4 · Accepted Answer

您需要使用空格字符：

var qw = '#middlecolumn';
$(qw + ' *').hide(); // will be equivalent to: "#middlecolumn *"

否则，插值会将其转换为: #middlecolumn*，这是无效的。

score 2 · Accepted Answer

2

你错过了一个空间：

$(qw + ' *').hide();

于 2013-04-14T10:35:52.470 回答

score 2 · Accepted Answer

您在选择器中缺少空格键。所以它会是

var qw = '#middlecolumn';

$(qw + ' *').hide(); // <<-- Spacebar before *

score 1 · Accepted Answer

1

你缺少一个空格字符。

这个：

$(qw + '*').hide();

一定是：

$(qw + ' *').hide();

于 2013-04-14T10:39:00.553 回答

4 回答 4