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我有三个表：LitHold、LitHoldDetails 和 EmailTemplate。定义如下。

CREATE TABLE [dbo].[LitHold](
[LitholdID] [int] IDENTITY(1,1) NOT NULL,
[LitHoldStatusID] [tinyint] NOT NULL,
[EmailReminderID] [tinyint] NULL,
[ApprovedDate] [datetime] NULL,
[TerminatedDate] [datetime] NULL,
CONSTRAINT [PK_Lithold] PRIMARY KEY CLUSTERED 
(
[LitholdID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]


CREATE TABLE [dbo].[LitHoldDetails](
[LitHoldDetailsID] [int] IDENTITY(1,1) NOT NULL,
[LitholdID] [int] NOT NULL,
[VersionID] [int] NOT NULL,
[Description] [varchar](300) NULL,
[ResAttorneyID] [varchar](10) NOT NULL,
[Comments] [varchar](1000) NULL,
[HoldStartDate] [datetime] NULL,
[HoldEndDate] [datetime] NULL,
[CreatedDate] [datetime] NOT NULL,
[CreatedByLogin] [varchar](10) NULL,
CONSTRAINT [PK_LitholdDetails] PRIMARY KEY CLUSTERED 
(
[LitHoldDetailsID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]


CREATE TABLE [dbo].[EmailTemplate](
[TemplateID] [int] IDENTITY(1,1) NOT NULL,
[LitHoldDetailsID] [int] NOT NULL,
[From] [varchar](50) NULL,
[To] [varchar](2000) NULL,
[CC] [varchar](500) NULL,
[BCC] [varchar](500) NULL,
[Subject] [nvarchar](200) NULL,
[MessageBody] [nvarchar](max) NULL,
[SendDate] [datetime] NULL,
[IsDefault] [bit] NOT NULL,
CONSTRAINT [PK_EmailTemplate] PRIMARY KEY CLUSTERED 
(
[TemplateID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

对于每个 LitHold，可以有多个 LitHoldDetails。对于每个 LitHoldDetail，应该有一个 EmailTemplate。我最近发现一些 LitHoldDetails 没有 EmailTemplates。我们仍在开发这个项目，所以这没什么大不了的。但是，我们希望将 EmailTemplate 数据放入数据库。情况是，对于每个 LitHold，至少有一个具有 EmailTemplate 的 LitHoldDetail。我想为 a) 具有相同 LitHoldID 和 b) 没有 EmailTemplate 的所有 LitHoldDetails 复制此 EmailTemplate 数据。我尝试过的一种方法是：

insert into EmailTemplate
(LitHoldDetailsID, [From], [To], CC, BCC, Subject, MessageBody, SendDate, IsDefault)
(select (select top 1 LitHoldDetailsID from LitHoldDetails where LitholdID = d.LitholdID and LitHoldDetailsID <> e.LitHoldDetailsID), [To], CC, BCC, Subject, MessageBody, SendDate, IsDefault from 
EmailTemplate e inner join LitHoldDetails d on e.LitHoldDetailsID = d.LitHoldDetailsID)

但这让我获得了一些 LitHoldDetails 的多行，具有不同的 EmailTemplate 数据，以及 LitHoldDetails 为 NULL 的一些行。我怎样才能做到这一点？我正在使用 SQL Server 2008。

4

1 回答 1

1

尝试插入：

SELECT lhd.LitHoldDetailsID, CloneEmailTemplate.[From], ... 
FROM LitHoldDetails lhd 
CROSS APPLY (SELECT TOP 1 et.*
             FROM EmailTemplate et
             JOIN LitHoldDetails lhd2 ON lhd2.LitHoldDetailsID = et.LitHoldDetailsID
             WHERE lhd2.LitHoldID = lhd.LitHoldID
            ) AS CloneEmailTemplate 
WHERE NOT EXISTS (SELECT 1 
                  FROM EmailTemplate et2 
                  WHERE et2.LitHoldDetailsID = lhd.LitHoldDetailsID
                 )
于 2013-04-12T18:31:07.827 回答