java - Jaxb 通配符编组编组

Question

首先对我糟糕的英语感到抱歉。我想解组而不是编组以下类。

@XmlSeeAlso({B1.class, C1.class})
public abstract class A1 implements Serializable {

private String parameterName;

  public A1 () {
  }


  public A1 (String parameterName) {
      this.parameterName = parameterName;
  }

  public String getParameterName() {
      return parameterName;
  }
}

子类

public class B1 extends A1{
@SuppressWarnings("rawtypes")
private Collection dataSource = new ArrayList();

public B1 () {

}


@SuppressWarnings("rawtypes")
public B1 (String parameterName, Collection dataSource) {
    super(parameterName);
    this.dataSource = dataSource;
}


@SuppressWarnings("rawtypes")
public B1 (Collection dataSource) {
    super("B");
    this.dataSource = dataSource;
}

@SuppressWarnings("rawtypes")
public Collection getDataSource() {
    return dataSource;
}

和

public class C1 extends A1 {

private String imagePath;


public C1() {

}

protected C1(String parameterName) {
    super(parameterName);
}


public C1 (String parameterName, String imagePath) {
    super(parameterName);
    this.imagePath = imagePath;
}

public String getImagePath() {
    return imagePath;
}

子类在一个集合中

List<? extends A1>

解组和编组后的字段将为空（例如：parameterName）。该应用程序不会引发任何异常。