32
var async = require('async');

function callbackhandler(err, results) {
    console.log('It came back with this ' + results);
}   

function takes5Seconds(callback) {
    console.log('Starting 5 second task');
    setTimeout( function() { 
        console.log('Just finshed 5 seconds');
        callback(null, 'five');
    }, 5000);
}   

function takes2Seconds(callback) {
    console.log('Starting 2 second task');
    setTimeout( function() { 
        console.log('Just finshed 2 seconds');
        callback(null, 'two');
    }, 2000); 
}   

async.series([takes2Seconds(callbackhandler), 
              takes5Seconds(callbackhandler)], function(err, results){
    console.log('Result of the whole run is ' + results);
}) 

输出如下所示:

Starting 2 second task
Starting 5 second task
Just finshed 2 seconds
It came back with this two
Just finshed 5 seconds
It came back with this five

我期待takes2Second 函数在takes5Second 开始之前完全完成。这就是它应该如何工作的方式。请告诉我。最后的功能永远不会运行。谢谢。

4

5 回答 5

41

不完全的。您正在立即执行函数(一旦评估了数组),这就是它们似乎同时启动的原因。

传递给每个要执行的函数的回调在异步库内部。一旦你的函数完成,你就执行它,传递一个错误和/或一个值。您不需要自己定义该功能。

在您的情况下,最终函数永远不会运行,因为 async 需要您调用以继续执行系列中的下一个函数的回调函数实际上从未被执行(只有您的callbackHandler函数被执行)。

试试这个:

async.series([
    takes2Seconds,
    takes5seconds
], function (err, results) {
    // Here, results is an array of the value from each function
    console.log(results); // outputs: ['two', 'five']
});
于 2013-04-12T10:41:28.793 回答
17

James 给了你一个很好的概述async.series。请注意,您可以在系列数组中设置匿名函数,然后使用参数调用您的实际函数

var async = require('async')
var param1 = 'foobar'
function withParams(param1, callback) {
  console.log('withParams function called')
  console.log(param1)
  callback()
}
function withoutParams(callback) {
  console.log('withoutParams function called')
  callback()
}
async.series([
  function(callback) {
    withParams(param1, callback)
  },
  withoutParams
], function(err) {
  console.log('all functions complete')
})
于 2013-04-13T14:29:11.703 回答
11

我创建异步系列的首选方法是使用操作数组,如下所示;

var async = require('async'),
    operations = [];

operations.push(takes2Seconds);
operations.push(takes5seconds);

async.series(operations, function (err, results) {
    // results[1]
    // results[2]
});

function takes2Seconds(callback) {
    callback(null, results);
}

function takes5seconds(callback) {
    callback(null, results);
}
于 2013-07-24T17:56:06.077 回答
7
async.series
    ([  
        function (callback)
        {
            response=wsCall.post(user,url,method,response);
            console.log("one");
            callback();
        }
        ,
        function (callback)
        {
            console.log("two");
            //console.log(response);
            callback();
        }
    ]
    ,
    function(err) 
    {
        console.log('Both a and b are saved now');
        console.log(response);
    });
于 2014-05-20T19:21:00.937 回答
4

async.series中,所有函数都被串行执行,每个函数的合并输出被传递给最终的回调。例如

var async = require('async');
async.series([
    function (callback) {
        console.log('First Execute..');
        callback(null, 'userPersonalData');
    },
    function (callback) {
        console.log('Second Execute.. ');
        callback(null, 'userDependentData');
    }
],
function (err, result) {
    console.log(result);
});

输出:

First Execute..
Second Execute..
['userPersonalData','userDependentData'] //result
于 2016-04-20T09:11:18.490 回答