1

在下面的代码中，我总是从地理编码 NSArray *placemarks 中返回一个对象。我做了一个 NSLog 它总是显示为一个对象。无论我在搜索栏中输入什么。

我正在我的 iPhone 5 设备上对其进行测试。我住在旧金山，设备地图工作得很好。即当我输入“星巴克”时，我只得到一个对象，它被称为“Álvaro Obregón，联邦区 01020” 附近至少有 10 家星巴克。 

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString {

    [geocoder geocodeAddressString:searchString completionHandler:^(NSArray* placemarks, NSError* error)

  if ([placemarks count] > 0) {
        NSLog(@"Number of objects in placemarks %i",placemarks.count);
        for (CLPlacemark* aPlacemark in placemarks)
        {
            self.street = aPlacemark.thoroughfare;
            self.city = aPlacemark.locality;
            self.state = aPlacemark.administrativeArea;
            self.zip = aPlacemark.postalCode;

            NSMutableString *result = [NSMutableString string];
            if (self.street)
                [result appendString:self.street];
            if (self.street && (self.city || self.state || self.zip))
                [result appendString:@", "];
            if (self.city)
                [result appendString:self.city];
            if (self.city && self.state)
                [result appendString:@", "];
            if (self.state)
                [result appendString:self.state];
            if (self.zip)
                [result appendFormat:@" %@", self.zip];
            placemarksArray = [[NSMutableArray alloc]init];
            [self.placemarksArray addObject:result];
            NSLog(@" This is result %@", result);

            [self.searchDisplayController.searchResultsTableView reloadData];
        }
    }

} 
 ]; 
return NO;

}

4

0 回答 0