我希望用户能够看到他们所有零工的名称和描述，然后能够从列表中选择每个零工的可用天数。本质上，我希望用户显示他们的奇数名称、描述、天数列表，然后是更新按钮，我希望在每个奇数作业的同一页面上重复此操作，以便用户可以看到他们的当前状态，更改它，选择一天并点击更新。
我正在尝试让多个列表在 php 中工作，但我不断收到此错误：
解析错误：语法错误，意外的 'DaysAvailable' (T_STRING)，期待 ',' 或 ';'
这与以下形式的代码行有关：
<select name="DaysAvailable[]" size="5" multiple="multiple" id="DaysAvailable[]">
更新页面：
<?php
if (isset($_POST['OddJobName']) && isset($_POST['Description']) && isset($_POST['DaysAvailable']) && empty($errors) === true){//if (empty($_POST) === false && empty($errors) === true) { //if (isset(empty($_POST['OddJobName'])) && isset(empty($_POST['Description'])) && isset(empty($_POST['DaysAvailable'])) === false && empty($errors) === true)
$daysavailable='';
foreach ($_POST['DaysAvailable'] as $value)
{
$daysavailable .=$value." ";
}
$update_data = array (
'MemberID' => $MemberID,//$session_MemberID,//,$_SESSION['MemberID']
'OddJobName' => $_POST['OddJobName'],
'Description' => $_POST['Description'],
'DaysAvailable' => $daysavailable,
);
update_user ($update_data);
if(success){
header('Location: member.php?username='.$username);
exit ();
}
} else if (empty($errors) === false){
//otherwise output errors
echo output_errors($errors);
}
?>
同一页面上的表格：
<form action="" method ="post" enctype="multipart/form-data">
<table width="100%" border="1" cellspacing="0" cellpadding="5">
<td width="50%">
<table width="100%" border="1" cellspacing="17" cellpadding="0">
<?php
$result = mysql_query("SELECT * FROM `oddjob` WHERE `MemberID` = $MemberID");
while($row = mysql_fetch_assoc($result))
{
echo "<tr>
<td>
<p>Service Name:</p>
</td>
<td>
<p>". $row['OddJobName']."</p>
</td>
</tr>
<tr>
<td>
<p>Description:</p>
</td>
<td>
<p>". $row['Description']."</p>
</textarea>
</td>
</tr>
<tr>
<td>
<p>Days Available(current week)*:</p>
<p>(hold Ctrl to select multiple)</p>
</td>
<td>
<select name="DaysAvailable[]" size="5" multiple="multiple" id="DaysAvailable[]">
"<option value="Monday">Monday</option>
<option value="Tuesday">Tuesday</option>
<option value="Wednesday">Wednesday</option>
<option value="Thursday">Thursday</option>
<option value="Friday">Friday</option>
<option value="Saturday">Saturday</option>
<option value="Sunday">Sunday</option>
</select>
</td>
<tr>
</table>
<input type='submit'value='update'><input type='button'value='Back to profile' onClick="history.go(-1);return true;"><!--http://www.computerhope.com/issues/ch000317.htm-->
</table>
</form>";
}
?>
更新功能：
function update_user($update_data){
global $MemberID;
$update = array();
array_walk($update_data, 'array_sanitize');
foreach($update_data as $field=>$data){ //loop through update data in update_info.php
$update[] = '`' . $field . '` = \'' . $data . '\'';
}
("UPDATE `oddjob` SET " . implode(', ', $update). " WHERE `MemberID` = $MemberID") or die (mysql_error());
}
请帮我实现这个，谢谢。