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仅使用 jquery 或 javascript 的条件下拉列表

场景：我有一个主下拉列表列表，如果我在下拉列表中选择“dropdownmain1”，它将显示下拉列表对应的“dropdownmain1”值

<select name="dropdownmain" id="" title="">
    <option value="dropdownmain1">dropdownmain1</option>
    <option value="dropdownmain2">dropdownmain2</option>
    <option value="dropdownmain3">dropdownmain3</option>
    <option value="dropdownmain4">dropdownmain4</option>
</select>



//if selected dropdownmain1 this dropdown will display
<select name="dropdownmain1" id="" title="">
    <option value="dropdownmain1-submenu1">dropdownmain1-submenu1</option>
    <option value="dropdownmain1-submenu2">dropdownmain1-submenu2</option>
    <option value="dropdownmain1-submenu3">dropdownmain1-submenu3</option>
    <option value="dropdownmain1-submenu4">dropdownmain1-submenu4</option>
</select>

//if selected dropdownmain2 this dropdown will display
<select name="dropdownmain2" id="" title="">
    <option value="dropdownmain2-submenu1">dropdownmain2-submenu1</option>
    <option value="dropdownmain2-submenu2">dropdownmain2-submenu2</option>
    <option value="dropdownmain2-submenu3">dropdownmain2-submenu3</option>
    <option value="dropdownmain2-submenu4">dropdownmain2-submenu4</option>
</select>

//if selected dropdownmain3 this dropdown will display
<select name="dropdownmain3" id="" title="">
    <option value="dropdownmain3-submenu1">dropdownmain3-submenu1</option>
    <option value="dropdownmain3-submenu2">dropdownmain3-submenu2</option>
    <option value="dropdownmain3-submenu3">dropdownmain3-submenu3</option>
    <option value="dropdownmain3-submenu4">dropdownmain3-submenu4</option>
</select>

//if selected dropdownmain4 this dropdown will display
<select name="dropdownmain4" id="" title="">
    <option value="dropdownmain4-submenu1">dropdownmain4-submenu1</option>
    <option value="dropdownmain4-submenu2">dropdownmain4-submenu2</option>
    <option value="dropdownmain4-submenu3">dropdownmain4-submenu3</option>
    <option value="dropdownmain4-submenu4">dropdownmain4-submenu4</option>
</select>

这可能仅使用 jquery 或 javascript 吗？

4

1 回答 1

5

是的，您可以使用 jquery 轻松完成。

$('select[name!="dropdownmain"]').hide();
$('select[name="' + $('select[name="dropdownmain"]').val() + '"]').show();
$('select[name="dropdownmain"]').change(function(){
    $('select[name!="dropdownmain"]').hide();
    $('select[name="' + $(this).val() + '"]').show();
});

http://jsfiddle.net/p7jyv/2/

还有一种更易读的方法：

var $topSelect = $('select[name="dropdownmain"]');
var $nestedSelects = $('select[name!="dropdownmain"]');
showApplicableSelect();
$topSelect.change(showApplicableSelect);
function showApplicableSelect() {
    $nestedSelects.hide();
    $('select[name="' + $topSelect.val() + '"]').show();
}

http://jsfiddle.net/p7jyv/5/

于 2013-04-11T13:09:49.453 回答