xml - XSLT practice example

Question

I'm studying for an exam, and I'd like to make sure I'munderstanding this correctly. Would the following print out ABC or just BC because the templates weren't applied to next/previous/item?

input.xml :

<?xml version="1.0" encoding="UTF-8"?>
<next>
    <previous>
        <item>A</item>
    </previous>
    <item>B</item>
    <item>C</item>
</next>

input.xsl :

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="/">
        <HowDoes>
            <xsl:apply-templates select="next/item" />
            <xsl:apply-templates select="previous/item" />
        </HowDoes>
    </xsl:template>
    <xsl:template match="item">
        <ThisWork>
            <xsl:copy-of select="." />
        </ThisWork>
    </xsl:template>
</xsl:stylesheet>

Answer 1

您的样式表将被忽略A，因为从文档根（您的第一个模板匹配的位置）的角度来看，有两个next/item节点但没有 previous/item节点。只有一个next/previous/item节点。

如果您将模板更改为

<xsl:template match="/">
    <HowDoes>
      <xsl:apply-templates select=".//item" />
    </HowDoes>
</xsl:template>

然后item将找到所有节点，因为它正在寻找当前节点的所有item 后代item，而不是子节点的所有子节点previous。